- #1
salman213
- 302
- 1
1. Hi I posted a previous question on this forum and it was answered well but I had another question about complex solutions/roots.
for example if i have a question like
z^2 = 1e^(j)(pie)
z = 1e^(j)(pie + 2kpie)^1/2 k =0,1
1. z = 1e^(j)(pie/2 ) = 0 + j
2. z = 1e^(j)(3pie/2) = 0 - j
if I test these solutions (0+j)(0+j) = -1 , (0 - j)(0 - j) = -1
they are correct but my question is are those angles correct?
another way to solve that question seems to be
z^2 = 1e^(j)(-pie)
z = 1e^(j)(-pie + 2kpie)^1/2 k =0,1
1. z = 1e^(j)(-pie/2 ) = 0 - j
2. z = 1e^(j)(pie/2) = 0 + j
if i go backwards
0 + j = 1e^(j)(-pie/2 ) and 0 - j = 1e^(j)(pie/2)so which angles are correct?
Like on an exam I don`t really know which angles I would write!
for example if i have a question like
z^2 = 1e^(j)(pie)
z = 1e^(j)(pie + 2kpie)^1/2 k =0,1
1. z = 1e^(j)(pie/2 ) = 0 + j
2. z = 1e^(j)(3pie/2) = 0 - j
if I test these solutions (0+j)(0+j) = -1 , (0 - j)(0 - j) = -1
they are correct but my question is are those angles correct?
another way to solve that question seems to be
z^2 = 1e^(j)(-pie)
z = 1e^(j)(-pie + 2kpie)^1/2 k =0,1
1. z = 1e^(j)(-pie/2 ) = 0 - j
2. z = 1e^(j)(pie/2) = 0 + j
if i go backwards
0 + j = 1e^(j)(-pie/2 ) and 0 - j = 1e^(j)(pie/2)so which angles are correct?
Like on an exam I don`t really know which angles I would write!