Calculate Acceleration of Thrown Baseball: 5.98s, 1.2m from Rest

In summary, the person threw the ball straight up and it was in the air for 5.98 seconds before returning to its initial height. To find the acceleration produced by the person's arm, we need to use a constant acceleration equation or a free fall equation, and first find the initial velocity of the ball. Then, we can use the distance of 1.2 m to determine the acceleration of the arm. A helpful resource for this problem can be found at the provided link.
  • #1
yankeekd25
27
0
A person throws a baseball straight up (in the y direction). The ball is in the air for 5.98 seconds before it returns to the same height from where it was initially released. If the person when throwing the ball, generated a constant acceleration over a distance 1.2 m from rest, what is the acceleration produced by the person's arm in m/s2?

I guess you have to use a constant acceleration equation or a free fall equation, but I do not know which one.
 
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  • #2
First of all find the initial velocity with which the ball is thrown up so that it will be in the air for 5.98 seconds.
Then find the acceleration of the arm which can produce this velocity with in the distance of 1.2 m.
 
  • #3
Check out this link, it may help you------>media.wiley.com/product_data/excerpt/88/.../0471713988.pdf
 

What is the formula for calculating acceleration?

The formula for calculating acceleration is a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

What is the unit for acceleration?

The unit for acceleration is meters per second squared (m/s^2).

How do you calculate acceleration of a thrown baseball with a time of 5.98 seconds and a displacement of 1.2 meters?

To calculate the acceleration of a thrown baseball with a time of 5.98 seconds and a displacement of 1.2 meters, we can use the formula a = (vf - vi)/t. Since the baseball starts from rest (vi = 0), the formula simplifies to a = vf/t. We also know that the displacement (d) is equal to the average velocity (v) multiplied by time (t), so we can rearrange the formula to vf = d/t. Plugging in the values, we get vf = 1.2m/5.98s = 0.20 m/s. Now, we can plug this value into the original formula to get a = 0.20 m/s / 5.98s = 0.0334 m/s^2. Therefore, the acceleration of the thrown baseball is 0.0334 m/s^2.

What is the significance of calculating acceleration of a thrown baseball?

Calculating the acceleration of a thrown baseball can help us understand the motion of the baseball and its velocity at any given time. This information can be useful in sports to improve pitching techniques or in physics experiments to study projectile motion.

Can the acceleration of a thrown baseball vary?

Yes, the acceleration of a thrown baseball can vary depending on factors such as air resistance, wind speed, and the force applied by the pitcher. It can also vary throughout the motion of the baseball as it may experience different levels of acceleration at different points in time.

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