- #1
mikep
- 43
- 0
can someone please help me with this problem?
A 10kg cart with low friction wheels has a 4000N/m
spring on one end. The cart is pressed against the
wall so that the spring is compressed 0.50m. The cart
is released and rolls on the surface only to hit
another identical cart. The two carts lock together
and run into a wall on the other side of the room
where a 4000N/m spring on the second cart compresses
until the carts stop. How far does the second spring
compress as the carts stop?
I think i need to break it up into three parts. For
the first one i need to find the force of the s[ring
then the collision of hte two carts and then the
compression of the spring. So for the first part i
did:
PEs = (1/2) k(x^2) = (1/2)(4000N/m)(0.50^2) = 1000J
is that right for the first part?
A 10kg cart with low friction wheels has a 4000N/m
spring on one end. The cart is pressed against the
wall so that the spring is compressed 0.50m. The cart
is released and rolls on the surface only to hit
another identical cart. The two carts lock together
and run into a wall on the other side of the room
where a 4000N/m spring on the second cart compresses
until the carts stop. How far does the second spring
compress as the carts stop?
I think i need to break it up into three parts. For
the first one i need to find the force of the s[ring
then the collision of hte two carts and then the
compression of the spring. So for the first part i
did:
PEs = (1/2) k(x^2) = (1/2)(4000N/m)(0.50^2) = 1000J
is that right for the first part?
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