How Do You Calculate Gravitational Force Between Earth and an Asteroid?

In summary: Gravitational Attraction has revealed that it can be calculated using the formula Fg = G(m1m2/s squared), where m1 and m2 represent the masses of the two objects, s is the distance between their centres, and G is the universal gravitational constant. In order to apply this formula, I researched the mass and radius of the Earth (6.0 * 10 to the 24th Kg and 6.3 * 10 to the 3rd Km, respectively) and an unknown asteroid (7.18 * 10 to the 7th Kg and 5.00 x 10 to the -1 Km). Using this information, I was able to fill out a chart with the
  • #1
lusterjester
4
0

Homework Statement


We just have learned about Gravitational Attraction. The formula (for those who don't know is Fg = G (m1m2/s Squared)
M meaning Mass
G meaning universital gravity
S meaning distance between

I had to research the mass/radius of the Earth. I was given the mass/radius of an unknown asteroid.

Earth mass = 6.0 * 10 to the 24th Kg
Earth Radius = 6.3 * 10 to the 3rd Km

Unknown Asteroid mass = 7.18 * 10 to the 7th
Radius = 5.00 x 10 to the -1.

We were given this chart to fill out that had the fallowing Catagories within it (i'll give a sample of the first row to give you all an idea).
----------------------------------------------------
Asteroid's Distance from the Earth's Surface
1.00 x 10 to the 3rd

Displacment between their centers (km)

Force of gravitational Attraction (N)
--------------------------------------------------------


Homework Equations



G = 6.667 x 10 to the -11
S squared = Square root of ( G(m1m2)/Fg)

The Attempt at a Solution



Now I know my information looks like this (at least I think it does)

m1 = 7.18 * 10 to the 7th
m2 = 6.0 * 10 to the 24th Kg
s squared = ?
G = 6.667 8 10 to the -11
Fg = ?

I've been totally lost ever since. I know I can't figure something out without having S or Fg all ready found. Any one have an answer for me?
 
Physics news on Phys.org
  • #2
Draw a picture.

In Newton's formula, S is the distance between the centres of mass of the two masses. You are given the distance between the surfaces. What is the distance between their centres? Just plug that into the formula.

AM
 
  • #3



I can confirm that the formula for gravitational attraction is indeed Fg = G(m1m2/s^2), where G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and s is the distance between their centers.

In order to calculate the force of gravitational attraction between the Earth and the unknown asteroid, we first need to convert the given values for mass and radius into SI units (kilograms and meters). The mass of the asteroid is 7.18 x 10^7 kg and its radius is 5.00 x 10^-1 km, which is equal to 5.00 x 10^2 m. The mass of the Earth is 6.0 x 10^24 kg and its radius is 6.3 x 10^3 km, which is equal to 6.3 x 10^6 m.

Next, we can use the formula s^2 = (G(m1m2))/Fg) to solve for the distance between the two objects. Plugging in the values for G, m1, and m2, we get s^2 = (6.667 x 10^-11 * 7.18 x 10^7 * 6.0 x 10^24)/Fg. We can rearrange this equation to solve for Fg, which is the force of gravitational attraction between the Earth and the asteroid.

Once we have found the value for Fg, we can use it to fill out the chart given in the homework, by plugging in the distance between the Earth and the asteroid (which we calculated above) and the displacement between their centers (which is simply the sum of the Earth's radius and the asteroid's radius). This will give us the force of gravitational attraction for different distances between the two objects.

I hope this helps you to better understand the concept of gravitational attraction and how to apply the formula to solve for unknown values. Keep up the good work in your studies!
 

1. What is gravitational attraction?

Gravitational attraction is the phenomenon by which two objects with mass are drawn towards each other. This force is directly proportional to the masses of the objects and inversely proportional to the square of the distance between them.

2. How does gravitational attraction work?

Gravitational attraction is governed by Newton's Law of Universal Gravitation, which states that every object in the universe exerts a gravitational pull on every other object. The strength of this force depends on the masses of the objects and the distance between them.

3. What is the difference between gravitational attraction and gravity?

Gravitational attraction refers to the force of attraction between two objects with mass, while gravity is the overall force of attraction between all objects in the universe. Gravity is the result of the cumulative effect of all gravitational attractions in the universe.

4. How does gravitational attraction affect the motion of objects?

Gravitational attraction is a conservative force, meaning that it does not dissipate energy and can only change the direction or speed of an object's motion. This force is responsible for the orbital motion of planets around the sun and the moon around the Earth.

5. Can gravitational attraction be shielded or canceled out?

Gravitational attraction is a fundamental force of nature and cannot be shielded or canceled out. However, the strength of this force can be reduced by increasing the distance between objects or by decreasing their masses.

Similar threads

  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
23
Views
2K
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
1K
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
1K
Back
Top