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zero_kilo
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so the amount of work done to drive the current through the inductor is given by
dw=Eidt where E is the emf of the variable voltage source.We put E=+L (di/dt).
can you please tell me why we put that value?? (i know the induced e.m.f on the inductor is - L (di/dt)
thanks
dw=Eidt where E is the emf of the variable voltage source.We put E=+L (di/dt).
can you please tell me why we put that value?? (i know the induced e.m.f on the inductor is - L (di/dt)
thanks