Calculating the pH of CO2 dissolved in 1l of waterby skaai Tags: buffer calculations, carbon dioxide, chemisrty, dissolved, water, weak acid 

#1
Feb1714, 07:51 AM

P: 16

OK folks,
first of all, let me thank those of you who have helped me with previous questions.... perhaps this is why I keep coming back! This time, I'm just asking those of you who are better than I am at this if I did this right and thus, got the correct result. I think I did, but since this is not a homework problem, I have no way of checking my answer... I set up my problem like this (see the attached diagram): Imagine our system has a beaker with 1 liter of water and is enclosed in a constantpressure (of 1 atm.) atmosphere of 100% carbon dioxide at 25°C. We let the carbon dioxide come to equilibrium with the water so the maximum dissolves. What would the resultant pH be? What do we know?
CO2 + 2H_{2}O → H_{2}CO_{3} + H_{2}O → HCO_{3}^{} + H_{3}O^{+}
1.45 g. CO_{2}[itex]\frac{1 mol.}{44.01 g.}[/itex]= 0.032947 mol. CO_{2}Calculate using a RICE table (see the attached image table): Convert pKa to Ka: 10^{pKa} = Ka → 10^{6.367} = Ka Ka (10^{6.367}) = [itex]\frac{[A][H+]}{[HA]}[/itex] = [itex]\frac{(x)(x)}{(0.0329x)}[/itex]can we apply the "rule of 500?": Rule of 500: if [itex]\frac{[HA]}{Ka}[/itex]>500, ignore any nonzero changes in "x" [itex]\frac{0.0329}{1x E6.367}[/itex]=76,594 >> 500 so yes.simplify Ka: 10^{6.367}=[itex]\frac{x²}{0.0329}[/itex] x²=10^{6.367}(0.0329)=1.41317x10^{8} x=√1.41317x10^{8}=1.18877x10^{4}=[H^{+}] pH = log[H^{+}]=log(1.18877x10^{4})=3.9249≈3.92so the lowest the pH can go in 1 liter of water in equilibrium with 100% CO_{2} at 25ºC and 1 atmosphere pressure is 3.92. It sounds like a reasonable number, or did I totally mess something up somewhere? thanks so much for any help on this! 



#2
Feb1714, 08:57 AM

Admin
P: 22,671

Looks OK to me.
Note that actually we don't know what is the concentration of carbonic acid in water  we can measure solubility and pH, but that allows only to calculate equilibrium constant for the overall reaction H_{2}O + CO_{2} <> H^{+} + HCO_{3}^{} but not for two separate ones: H_{2}O + CO_{2} <> H_{2}CO_{3} H_{2}CO_{3} <> H^{+} + HCO_{3}^{} We often do assume all carbon dioxide dissolved is present in the form of carbonic acid, that yields commonly known Ka1 value. As it yields a correct calculation results we simply don't care about reality. 



#3
Feb1814, 06:24 AM

P: 16

I see your point about carbonic acid... it's so mysterious, but all we can do is like with dark matter... infer its there from the effects...
thanks so much for the onceover! 


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