Distribution of speeds in a molecular beam.

In summary, the formula is derived from the Maxwell-Boltzmann distribution and takes into account the total number of particles, the number of particles crossing an area in a given time, and the direction and speed of the particles.
  • #1
Narcol2000
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I'm struggling to understand the basis for the following formula.

The goal is to find the distribution of molecular speeds emerging from a smal hole in an oven where molecules are allowed to come to thermal equalibrium with the oven walls before exiting through the small whole.

The book states:

'Suppose we consider particles with speed in the range u to u+du which cross an area A at an angle [tex]\theta[/tex] to the normal to the area. In a time t they travel a distance ut and sweep out a volume [tex]Autcos(\theta)[/tex]. The number of particles in this volume with speeds in the range u to u+du and whose direction of motion lies in the range [tex]\theta[/tex] to [tex]\theta + d\theta[/tex] and [tex]\phi[/tex] to [tex]\phi + d\phi[/tex] is:

[tex]Autcos(\theta)\frac{n(u)du}{V}\frac{d\theta sin(\theta)d\phi}{4\pi}[/tex]

where n(u) is the Maxwell distribution and V i assume is the total volume of the oven (i think... its not actually stated what the volume V is.)

I don't see where this formula comes from since it is just stated with no derivation, and would like to have some idea of where it comes from so any help would be appreciated.
 
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  • #2
The formula is derived from the Maxwell-Boltzmann distribution, which describes the probability of finding particles with a given energy at thermal equilibrium. The formula you've provided takes into account the total number of particles in the volume V of the oven, and the number of particles that cross an area A in a given time t. The d\theta and d\phi terms are used to account for the direction of the particles, while the cos(\theta) term accounts for the angle at which they cross the area A. Finally, the n(u)du term takes into account the number of particles in the range u to u+du. So the entire formula gives the probability of finding a particle with speed in the range u to u+du, crossing an area A at an angle \theta to the normal to the area, and whose direction of motion lies in the range \theta to \theta + d\theta and \phi to \phi + d\phi.
 
  • #3


The formula that is stated in the book is a simplified version of the Maxwell-Boltzmann distribution, which is a fundamental equation in statistical mechanics that describes the distribution of speeds for a gas in thermal equilibrium at a given temperature. The formula is derived from the principles of statistical mechanics, which use probabilities and statistical methods to describe the behavior of a large number of particles.

In the context of the molecular beam, the formula is used to calculate the number of particles with a certain speed and direction that will pass through the small hole in the oven. The first term, Autcos(\theta), represents the volume of the beam that is swept out by the particles with speeds in the range u to u+du. The second term, n(u)du/V, is the probability of finding a particle with a speed in the range u to u+du, which is given by the Maxwell distribution. The third term, d\theta sin(\theta)d\phi/4\pi, represents the solid angle that the particles are passing through as they exit the small hole.

Overall, the formula takes into account the volume of the beam, the probabilities of finding particles with different speeds, and the solid angle of the beam to calculate the distribution of speeds for the molecules exiting the oven. It is a result of statistical mechanics and is based on the principles of probability and statistical analysis. I hope this helps to clarify the basis of the formula for you.
 

1. What is a molecular beam?

A molecular beam is a stream of gas molecules moving at high velocities in a vacuum. It is used in experiments to study the properties and behavior of individual molecules.

2. How are molecular beams generated?

Molecular beams are generated using a device called a molecular beam source, which consists of a heated oven or a supersonic nozzle. The gas molecules are heated and then collimated into a narrow beam using a series of skimmers and apertures.

3. Why is the distribution of speeds in a molecular beam important?

The distribution of speeds in a molecular beam is important because it affects the outcome of experiments. The properties and behavior of molecules can vary depending on their speed, so having a controlled and uniform speed distribution is crucial for obtaining accurate results.

4. How is the distribution of speeds in a molecular beam measured?

The distribution of speeds in a molecular beam can be measured using a variety of techniques such as time-of-flight spectroscopy, velocity map imaging, and laser-induced fluorescence. These methods involve detecting and analyzing the velocities and energies of the molecules in the beam.

5. Can the distribution of speeds in a molecular beam be controlled?

Yes, the distribution of speeds in a molecular beam can be controlled by adjusting the temperature and pressure of the molecular beam source, as well as the design of the skimmers and apertures. This allows for the production of molecular beams with specific speed distributions for different experimental purposes.

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