Induced EMF: Solenoid in Square Loop

In summary, the problem involves a solenoid with N turns of wire and a square loop of wire with a side length of c. The solenoid has a radius of a and length of b, and its current varies according to I(t)= I_{0}(1 - e^-\alphat) where I_{0} and \alpha are positive constants. The induced EMF in the square loop can be found using the equation \epsilon = -N\frac{d\phi}{dt}. To find the magnetic field, Ampere's circuital law can be used and then integrated to find the electric flux and finally the inductance. The solenoid and cylinder are assumed to be the same.
  • #1
triplebeem1
2
0

Homework Statement



The solenoid has N turns of wire around a cylinder. The radius of the cylinder is "a" and length is "b." THe current of the solenoid varies as I(t)= I[tex]_{0}[/tex](1 - e^-[tex]\alpha[/tex]t) . I[tex]_{0}[/tex] and [tex]\alpha[/tex] are positive constants. Around the solenoid is a square loop of wire with side length "c." The axis of the square loop is parallel to and coincides with the axis of the solenoid. What is the magnitude of the induced EMF in the square loop?





Homework Equations



[tex]\epsilon[/tex] = -N[tex]\frac{d\phi}{dt}[/tex]




The Attempt at a Solution



[tex]\epsilon[/tex] = -N[tex]\frac{d\phi}{dt}[/tex]

d[tex]\epsilon[/tex] = -N[tex]\frac{dBA}{dt}[/tex]

[tex]\epsilon[/tex] = -NA[tex]\int[/tex]dB

[tex]\epsilon[/tex] = (-NA)[([tex]\mu[/tex]NI)/B]
 
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  • #2
Thats not strictly correct. The magnetic field of the solenoid is not a constant which you can integrate as you did. You are given the constants a and b for a reason. You can find the magnetic field by using ampere's circuital law. That is what you must integrate.
 
  • #3
Would I need to use the B-field of the solenoid to find the electric flux and then finally the inductance? I think I'm having a hard time grasping the concept of the question. I'm assuming the solenoid and cylinder are the same. Is that what you assume as well?
 
Last edited:

1. What is induced EMF in a solenoid in a square loop?

Induced EMF refers to the electromotive force that is created when there is a change in magnetic flux through a circuit. In the case of a solenoid in a square loop, the magnetic flux is created by the changing current in the solenoid, which induces an EMF in the loop.

2. How is induced EMF calculated?

Induced EMF can be calculated using Faraday's Law, which states that the induced EMF is equal to the negative rate of change of magnetic flux through the circuit. In the case of a solenoid in a square loop, the induced EMF can be calculated by multiplying the number of turns in the loop by the rate of change of magnetic flux through the solenoid.

3. What factors affect the magnitude of induced EMF?

The magnitude of induced EMF depends on the rate of change of magnetic flux through the circuit, as well as the number of turns in the loop. It is also affected by the strength of the magnetic field and the size of the loop.

4. How is induced EMF used in practical applications?

Induced EMF has many practical applications, such as in generators, transformers, and motors. It is also used in devices like metal detectors and induction cooktops. In these applications, induced EMF is used to convert mechanical energy into electrical energy or vice versa.

5. How can induced EMF be minimized?

Induced EMF can be minimized by reducing the rate of change of magnetic flux through the circuit. This can be achieved by using materials with low electrical conductivity, using laminated cores in transformers, or by adding a magnetic shield around the circuit to reduce the external magnetic field.

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