- #1
leehom
- 24
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Dubbie is moving directly along a normal line toward a plain mirror at a speed of 3.5 m/s, what is the speed of the image relative to Dubbie?
v Dubbie + v mirror = v image
3.5 m/s + 3.5 m/s = 7.0 m/s
What is the speed of the image, relative to Dubbie, if Dubbie walk away from the mirror surface at 3.5 m/s at an angle of 300 to the mirror surface?
Given:
θ = 300
v= 3.5 m/s
x/v= sinθ
x/(3.5 m/s) = sin300
x = [(3.5 m/s) sin300]
x = 1.75 m/s
v Dubbie + v mirror = v image
3.5 m/s + 3.5 m/s = 7.0 m/s
What is the speed of the image, relative to Dubbie, if Dubbie walk away from the mirror surface at 3.5 m/s at an angle of 300 to the mirror surface?
Given:
θ = 300
v= 3.5 m/s
x/v= sinθ
x/(3.5 m/s) = sin300
x = [(3.5 m/s) sin300]
x = 1.75 m/s