- #1
Ceres629
- 6
- 0
I'm stuck on a seemingly simple part of a proof (a proof showing there are no non zero solutions of the equation a^2 + b^2 = 3(s^2 + t^2)
at one step it says if
a^2 + b^2 = 3(s^2 + t^2) this implies
both a and b must be divisible by 3.
I tried to prove this myself but have had no luck...
any ideas?
at one step it says if
a^2 + b^2 = 3(s^2 + t^2) this implies
both a and b must be divisible by 3.
I tried to prove this myself but have had no luck...
any ideas?