Normed space and its double dual

In summary, the relationship between Y^* and X^* is that Y^* can be identified with a quotient of X^* by a subspace K. The Hahn-Banach theorem allows us to extend elements of Y^* to X^*, making the map X^*->Y^* onto. In the case of a Hilbert space, X^* can be decomposed into the sum of K and its orthogonal complement K', which is isomorphic to Y^*. However, this decomposition may not hold in general.
  • #1
dmuthuk
41
1
Hi, I am trying to sort out a few things about the dual and double dual of a normed space which has got me a little confused.

Given a normed space [tex]X[/tex] over [tex]\mathbb{R}[/tex], if [tex]Y[/tex] is a subspace of [tex]X[/tex], what is the relationship between [tex]Y^*[/tex] and [tex]X^*[/tex]? Can [tex]Y^*[/tex] be identified with some subspace of [tex]X^*[/tex]?

Also, we have the natural embedding of [tex]X[/tex] into [tex]X^{**}[/tex] given by the map [tex]x\mapsto\hat{x}[/tex] where [tex]\hat{x}:X^*\to\mathbb{R}[/tex] is evaluation at [tex]x[/tex]. How do we use this to define the natural embedding of [tex]Y[/tex] into [tex]Y^{**}[/tex]? Here is my idea: We want to send [tex]y[/tex] to [tex]\hat{y}_Y:Y^*\to\mathbb{R}[/tex]. So, we define [tex]\hat{y}_Y[/tex] as follows. For [tex]y^*\in Y^*[/tex], choose an arbitrary extension [tex]x^*\in X^*[/tex] (we can use Hahn-Banach here). Then, we say [tex]\hat{y}_Y(y^*):=\hat{y}(x^*)[/tex]. Does this depend on the choice of extension [tex]x^*[/tex]?
 
Physics news on Phys.org
  • #2
dmuthuk said:
Given a normed space [tex]X[/tex] over [tex]\mathbb{R}[/tex], if [tex]Y[/tex] is a subspace of [tex]X[/tex], what is the relationship between [tex]Y^*[/tex] and [tex]X^*[/tex]? Can [tex]Y^*[/tex] be identified with some subspace of [tex]X^*[/tex]?
Elements of X* are linear maps X->R, so can also be considered as elements of Y* by restriction to Y.
This gives a canonical map X*->Y*.

The kernel of the map, say K, consists of those elements of X* which map all of Y to 0. Also, the Hahn-Banach theorem says that any element of Y* can be extended to a continuous linear map X->R. So, X*->Y* is onto.

These facts are enough to conclude that Y* is isomorphic to X*/K. i.e. a quotient, not a subspace, of X*.

If X is a Hilbert space, then X* will also be a Hilbert space (isomorphic to X), in which case X* can be decomposed as the sum of K and its orthogonal complement K', which will be isomorphic to Y*. Don't think that X* can be decomposed like this in general though.
 

1. What is a normed space?

A normed space is a mathematical concept that refers to a vector space equipped with a norm, which is a function that assigns a non-negative length or magnitude to each vector in the space. This allows for the measurement of distance and direction within the space.

2. What is the double dual of a normed space?

The double dual of a normed space is the space of continuous linear functionals on the dual space of the original normed space. In other words, it is the set of all linear transformations from the dual space to the base field that are also continuous with respect to the dual norm.

3. How is the double dual related to the original normed space?

The double dual is a natural extension of the original normed space, as it contains all the information about the original space and its dual. In fact, the double dual can be seen as a completion of the original space, as it contains all the "missing" elements that were not in the original space.

4. Why is the concept of a double dual important in mathematics?

The double dual is important because it allows for the study of normed spaces in a more general and abstract way. It also has many applications in functional analysis, which is a branch of mathematics that deals with infinite-dimensional vector spaces and their associated operations and transformations.

5. Is every normed space isomorphic to its double dual?

No, not every normed space is isomorphic to its double dual. A normed space is isomorphic to its double dual if and only if it is reflexive, meaning that every bounded linear functional on the space can be represented as an inner product with a vector in the space itself. This condition is not satisfied by all normed spaces.

Similar threads

  • Linear and Abstract Algebra
2
Replies
52
Views
2K
  • Linear and Abstract Algebra
Replies
8
Views
1K
  • Calculus and Beyond Homework Help
Replies
0
Views
448
  • Linear and Abstract Algebra
Replies
10
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
458
  • Linear and Abstract Algebra
Replies
8
Views
871
  • Calculus and Beyond Homework Help
Replies
9
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
516
  • Linear and Abstract Algebra
Replies
1
Views
917
  • Linear and Abstract Algebra
Replies
14
Views
3K
Back
Top