- #1
Phoresis
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Ok, I haven't done maths for a few years now and I've been set the following question:
The sum of the first integers is given by:
Sum(n) = 1+2+3+4 ... +n = n(n+1)/2
Find similar formulae for
Even(n) = 2+4+6+8 ... +2n
Odd(n) = 1+3+5+7 ... +(2n-1)
Now the formulae I have come up with, by trial and error mind, are:
Even = n(n+2)/4
Odd = n(n)/4
Am I on the right lines here? And if so is there a mathematical way of coming up with these formuale that doesn't involve trial and error?
cheers
The sum of the first integers is given by:
Sum(n) = 1+2+3+4 ... +n = n(n+1)/2
Find similar formulae for
Even(n) = 2+4+6+8 ... +2n
Odd(n) = 1+3+5+7 ... +(2n-1)
Now the formulae I have come up with, by trial and error mind, are:
Even = n(n+2)/4
Odd = n(n)/4
Am I on the right lines here? And if so is there a mathematical way of coming up with these formuale that doesn't involve trial and error?
cheers