Calculating compressed air expansion when heated

In summary, if a biomass wood furnace is fed with 300m3/hr of compressed air at 8 bar, then the air flow xxxm3/hr out of the gas outlet will be expected to be 4.5m3/min.
  • #1
mellotango
33
0
Can anyone help me with this calculation? I'm trying to figure out how much compressed air (generated from screw compressor) will expand by a ratio of what when fed into a wood furnace.

1) Wood Furnace Fuel Input: 30kg dry wood fuel/hr
2) Compressed Air Pressure: 8 bar
3) Compressed Air Flow: 5m3/min or 300m3/hr

If compressed air at 8 bar is pumped into an enclosed furnace at rate of 300m3/hr, what air flow xxxm3/hr, do I expect to come out from the other end after heat expansion? My normal atmospheric air temperature is about say 24C.

Thx in advance
 
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  • #2
This does not compute. If the system is closed, there can be no expansion. And the pressure can't rise through the furnace; it can only drop as it flows. Or is it open to atmosphere?

And is the compressor flow in actual or standard (corrected to atmospheric pressure) units?

We'll need more detail about what your system looks like and what exactly you are trying to accomplish if we are to help.
 
  • #3
Sorry, there is a 6 inch outlet for the hot gases to escape. I'm trying to model a biomass wood furnace, to feed it with highly compressed air, and through a special mechanism, the forced air will be able to drive 2 shafts. One shaft will power a screw compressor, which feeds the compressed air into the furnace. And the other shaft will power an electrical alternator to generate electricity. Works similar like a gas turbine based on brayton cycle but parameters different as the heat energy output of wood is less than natural gas. The back work ratio of the compressor and alternative is split about 50:50. i.e. the shaft work is divided equally among these 2 components. Of course, there is will some lost shaft power due to heat loss.

Hence if the biomass furnace consumes 30kg of dry wood per hour. And in conventional green power generators, 1 kg of wood would roughly generate about 1 kwh of electrical power based on ~30% efficiency. Hence a 30 kwh alternator is needed. And since the ratio of the alternator and air compressor is 50:50, I deduce that a 30 kw screw compressor would also be needed. And from manufacturers specs, a 30 kw compressor would output about 4.5m3/min of compressed air of 0.8mpb/ 8 bar pressure.

So I'm gather to gather enough calculation for a computer simulation program. And I need to find out how much the compressed air expands by when it exits the gas outlet and the calculation to do this. Hope you can help.
 
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1. How do you calculate the expansion of compressed air when heated?

To calculate the expansion of compressed air when heated, you can use the ideal gas law formula: PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin. By inputting the initial conditions and the final temperature, you can solve for the final volume.

2. What is the ideal gas law formula?

The ideal gas law formula is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin. This formula describes the relationship between the physical properties of gases at a constant temperature.

3. How does temperature affect the expansion of compressed air?

As temperature increases, the molecules in the compressed air have more kinetic energy and move faster. This causes them to collide with each other and the walls of the container more frequently and with greater force, leading to an increase in pressure and volume. Therefore, as temperature increases, the expansion of compressed air also increases.

4. What are the units of measurement for the ideal gas law formula?

The units of measurement for the ideal gas law formula are: P (pressure) in Pascals (Pa), V (volume) in cubic meters (m³), n (moles) in moles (mol), R (gas constant) in Joules per mole-Kelvin (J/mol-K), and T (temperature) in Kelvin (K).

5. Can the ideal gas law be applied to all gases?

The ideal gas law is most accurate for gases that are at low pressure and high temperature, and whose molecules have negligible volume compared to the volume of the container. However, it can still be used to approximate the behavior of most gases under ordinary conditions.

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