Question about gears and torque

In summary: Yes, that's what my professors always did - they got their gears from the Ideal Hardware store. You know the place, they sell frictionless pullies, massless ropes, etc. Absolutely essential stuff to teach physics....um, ok...sure, why not.
  • #1
Mr 4738
6
0
So this is something I've been thinking about...

Let's say you have an engine and a motor.

The engine has high torque (let's just say 3,000 ft/lb) and low RPM (2 RPM) and you attach a huge gear to the end of it (10 ft circumference). A very small gear (1 inch circumference) is attached to the motor. So the engine turns this huge gear 2 times a minute and the huge gear turns the small gear 240 times a minute.

So, the part I'm wondering now is that is there a loss of torque now that the new RPM is 240 and no longer 2 going into the motor? I'm thinking that since there is no slippage of the gears the torque will remain at 3,000 ft/lb going into the motor and it will now be at 240 RPM as well. Is this right or am I missing something?
 
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  • #2
If the torque were a static 3000lb/ft then yes, it would be divided by 120 on the static smaller gear.

However, since you are talking about torque over time with motion you're talking about energy. If you could design magical gears that keep the torque loss at 0 but were equally efficient then you would have to have an RPM loss in the smaller gear to adjust for the small amount of energy lost in friction of the gear teeth meshing and what not.
 
  • #3
ChmDudeCB said:
If the torque were a static 3000lb/ft then yes, it would be divided by 120 on the static smaller gear.

However, since you are talking about torque over time with motion you're talking about energy. If you could design magical gears that keep the torque loss at 0 but were equally efficient then you would have to have an RPM loss in the smaller gear to adjust for the small amount of energy lost in friction of the gear teeth meshing and what not.

In the first part what do you mean by static? I think you might be getting at what I'm looking for in the second part. How is there torque loss?
 
  • #4
If there are no losses, then the torque on the small gear will be 2/240 of the large gear.

In reality the torque is transferred between the gears via a linear force, which is opposed by friction between the gears. The force on the smaller gear's teeth will be reduced by the opposing friction force, and the torque on the smaller gear will end up being reduced.

static
What he meant is if the motor were producing a torque without movement. If there is no movement, then there would be no losses due to friction.
 
  • #5
I'm not sure what ChmDude is getting at, but gearing provides mechanical advantage, just like a lever: when you multiply distance, you divide force (torque) and vice versa. So if you start with 3000 ft-lb (not ft/lb) and go from 2 to 240 rpm, the torque is 3000/240=12.5 ft-lb of torque.
 
  • #6
russ_watters said:
I'm not sure what ChmDude is getting at, but gearing provides mechanical advantage, just like a lever: when you multiply distance, you divide force (torque) and vice versa. So if you start with 3000 ft-lb (not ft/lb) and go from 2 to 240 rpm, the torque is 3000/240=12.5 ft-lb of torque.
It would be 3000/120 which is 25lb/ft if the gears weren't moving.

Once the gears start moving you will see losses in torque due to friction between the surfaces of the gears, movement of lubrication on the surface, etc...

That lever you cited has 100% force transfer until you start to move the load up or down, then some of the force is lost to friction at the fulcrum.
 
  • #7
ChmDudeCB said:
It would be 3000/120 which is 25lb/ft if the gears weren't moving.

Once the gears start moving you will see losses in torque due to friction between the surfaces of the gears, movement of lubrication on the surface, etc...

That lever you cited has 100% force transfer until you start to move the load up or down, then some of the force is lost to friction at the fulcrum.
Basically correct, but since we know nothing about what the friction is going to be and it isn't helpful in explaining the theory, we assume a lossless situation for the purpose of the explanation.
 
  • #8
russ_watters said:
...since we know nothing about what the friction is going to be and it isn't helpful in explaining the theory, we assume a lossless situation for the purpose of the explanation.

Yes, that's what my professors always did - they got their gears from the Ideal Hardware store. You know the place, they sell frictionless pullies, massless ropes, etc. Absolutely essential stuff to teach physics.
 
  • #9
...um, ok...sure, why not.
 

1. What is the relationship between gears and torque?

The relationship between gears and torque is that gears can increase or decrease the amount of torque in a system. When two gears are meshed together, the smaller gear (pinion) will rotate faster than the larger gear (gear), resulting in an increase in torque output. Conversely, if the pinion is larger than the gear, the torque output will decrease.

2. How do gears affect the speed of rotation?

Gears affect the speed of rotation by changing the gear ratio. The gear ratio is the ratio of the number of teeth on the input gear to the number of teeth on the output gear. A higher gear ratio (such as 2:1) means the output gear will rotate twice for every one rotation of the input gear, resulting in a slower speed of rotation. A lower gear ratio (such as 1:2) means the output gear will rotate half as much as the input gear, resulting in a faster speed of rotation.

3. What is the purpose of a gear train?

The purpose of a gear train is to transmit and modify torque and rotational speed from one component to another in a system. This allows for efficient power transfer and control over the speed and direction of rotation. Gear trains are commonly used in machines such as cars, bicycles, and clocks.

4. How do you calculate the torque output of a gear system?

The torque output of a gear system can be calculated by multiplying the torque input by the gear ratio. For example, if the input torque is 10 Nm and the gear ratio is 2:1, the output torque would be 20 Nm. It is important to note that this calculation assumes no energy losses due to friction or other factors.

5. What are the different types of gears?

There are several different types of gears, including spur gears, helical gears, bevel gears, worm gears, and planetary gears. Spur gears are the most common and have straight teeth that are parallel to the axis of rotation. Helical gears have angled teeth for smoother operation and can transmit higher loads. Bevel gears are used to transmit power between intersecting shafts. Worm gears have a screw-like design and are used for high torque applications. Planetary gears consist of multiple gears rotating around a central gear and are used in applications requiring high gear ratios.

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