How can I override my instance variable of array type

In summary, the conversation discussed a problem with inheritance in which a base class contains a member variable and an abstract method, and a subclass is created to inherit from the base class. The question was about overriding the array variable in the subclass and using it as a return value. The suggested solutions included initializing the array in the subclass constructor, rethinking the class hierarchy, and using a protected variable in the parent class. The possibility of passing the array into the parent class constructor was also mentioned.
  • #1
walnutTree
5
0
Hi All,

Sorry to bother anyone, but I have run into a inheritance problem.
I have a base class which contains a member variable of array type, and an abstract method. Subsequently I created a sub class which derived from the base class. And I provide implementation for the abstract methods in the parent class. And I would like to override my array variable in the sub class, and use it as return value of .


Is there any way to able to override my variable?

here is my base class

Code:
public abstract class Parent{
	String[] labels;
	public Parent()
		{
			getLabels();
		}
	public abstract String[] getLabels();
}


and the following code contains the sub class with the main function:

Code:
public class Child extends Parent{
	String[] labels ={"name", "nickname", "birth"};
	public String[] getLabels()
	{
	   System.out.println("labels:  " + labels);	
	   return labels;	
	}
	
	public static void main(String[] args)	
	{
		new Child();
	}
}
 
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  • #2
Hi Walnut
Code:
String[] labels ={"name", "nickname", "birth"};
is hiding Parent's version of labels you can't access it from Child. What you can do is initialize it in the constructor
Code:
public class Child extends Parent{
	Child()
	{
	labels = new String[]{"name", "nickname", "birth"};
	}
}
 
Last edited:
  • #3
walnutTree,

Your extension of Parent is a bit odd. You are effectively saying that all children are parents. You might want to rethink your class names or what you're trying to do.

The other danger in the code is the lack of private, protected or public for your labels variable. Global class variables should never be public unless there is a need. In this case, if you should make it protected in your Parent class. Then you can set it in the Child constructor like genepool showed in his second code block.
 
  • #4
Hi guys,

Sorry for my late reply I was busy.
Thanks your answers or suggestions, these were quite useful. If I remove the getLabels() line from the Parent's constructor and initialize it in the Child constructor, it will works properly.

Parent:
Code:
public abstract class Parent{
	String[] labels;
	public Parent() {}
	public abstract String[] getLabels();
}

Child:
Code:
public class Child extends Parent{
	public Child()
		{	
		 labels = new String [] {"name", "nickname", "birth"};
		 getLabels();
		}
	public String[] getLabels()
		{
 	   		System.out.println("labels:  " + labels.length);	
			return labels;	
		}
	public static void main(String[] args)	
		{
		new Child();
		}	}

But I would like to leave that line in the Parent's constructor, because I want to create more subclasses with the different content of labels array.

e.g.

  • - labels = { "name", "birth"}
  • - labels = { "name, "birth", "color"}

Therefore I'm afraid I forget to call the getLabel() function from every subclass. I would be happy if child subclasses could inherit the getLabel() methods from the Parent.
Is there any way to achieve this?

Thanks in advance for your help
 
  • #5
I haven't done any Java in awhile, but I'm a bit confused by your code, this seems more logical to me:

Code:
public abstract class Parent
{
	// this variable is not accessible by the Child class, but each time you instantiate a Child, it will have it's own copy of this variable available via the public methods.
	private String[] labels;

	// the Parent constructor fills the label array
	public Parent(String[] newLabels)
	{
		labels = new String[newLabels.length()];

		for(int i = 0; i < newLabels.length(); i++)
		{
			labels[i] = newLabels[i];
		}
	}

	// this method returns the label array
	public String[] getLabels() { return labels; }
}

public class Child
{
	// the Child constructor calls the Parent constructor to fill the array it can't see
	public Child(String[] newLabels)
	{
		super(newLabels);
	}

	// the getLabels() function is inherited by the Child class, you don't have to override it to use it.

	public static void main(args[])
	{
		// declare a temp array to hold your labels
		String[3] labels = {"name", "nickname", "birth"};

		// instantiate a Child class and give it the labels
		Child myChild = new Child(labels);

		// this is a temp array to hold the labels that are returned.
		String[3] get_the_labels = myChild.getLabels();

		// print the labels
		for(int i = 0; i < get_the_labels.length(); i++)
		{
			System.out.println("label "+i+" : "+get_the_labels[i]+"\n");
		}
	}
}
 
Last edited:
  • #6
If your getLabels() method will always return the labels array of strings then I can't see why you would not do it the easy way as Adyssa has done and placed the getLabels() method in the parent class. That way you only need to override it if it will return something different.

As Borg pointed out though, your hierarchy might need some revisiting. What you are saying is that a child is-a parent. It might be better for example that a parent is-a person, a child is-a person and a child has-a parent?
By your Child class extending your Parent class you are saying that a Child is a type of a parent.
 
  • #7
walnutTree,

You're current code is about as clean as you can get it. Your abstract getLabels() method will guarantee that you have to implement it in every class that extends Parent. You won't be able to forget it because the code will break and the error will tell you about it. Also, if you forget to set the String array variable, you'll get a NullPointerException when you try to do anything it.

Again, I would make the labels variable in the Parent class a protected variable. That way you can set it from the child but you can't accidently change it from another class. Those types of errors can be hard to diagnose sometimes.

You could pass the labels into the parent as Adyssa has done but, the code inside of Adyssa's Parent constructor is completely unnecessary. If you wanted to pass in the array to the constructor, you would just do this:
labels = newLabels;
 
  • #8
Oh that's true, I don't know why I copied the array manually! >.>
 

1. How can I override my instance variable of array type?

To override an instance variable of array type, you can simply reassign a new array to the variable. For example, if your instance variable is named "myArray" and you want to override it with a new array, you can use the following code:

myArray = [1, 2, 3];

This will replace the previous array with the new one.

2. Can I override an instance variable of array type with a different data type?

No, an instance variable of array type can only be overridden with another array. You cannot assign a different data type to it, such as a string or integer.

3. Can I override a specific element in an instance variable of array type?

Yes, you can override a specific element in an instance variable of array type by accessing that element using its index and assigning a new value to it. For example, if you want to override the second element in an array named "myArray" with the value 5, you can use the following code:

myArray[1] = 5;

Note that array indices start at 0, so the second element has an index of 1.

4. Will overriding my instance variable of array type affect other variables that refer to the same array?

Yes, because arrays are objects in JavaScript, if you have multiple variables that refer to the same array, overriding the instance variable will also change the array for the other variables. This is because they all point to the same location in memory.

5. Is there a way to override an instance variable of array type without losing its original value?

Yes, you can use the spread operator (...) to create a copy of the original array and then add or remove elements from it. This will allow you to override the instance variable without losing its original value. For example:

myArray = [...myArray, 4, 5];

This will create a new array with all the elements from the original array and add the numbers 4 and 5 to the end of it.

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