- #1
iq2150
- 4
- 0
Guys, I'm trying (just for fun) to map out quantitatively from each traveller's perspective what happens in the following situation. Imagine the classic twins paradox, with triplets instead of twins, but not for the purposes of avoiding the turn-around. In my question, Triplet A stays on Earth, Triplet B travels in +X, turns around and returns to Earth, and Triplet C travels in -X a path exactly symmetric to the one traveled by Triplet B, turning around at the same time as measure on Earth. Eventually the traveling triplets reunite on earth, at the same time measured in the Earth frame.
When the triplets reunite, I'm hapy that B and C are the same age as each other and both younger than A, BUT: how does the clock of C look from B's perspective? This must be the same as how the clock of B looks from C's perspective, even though B and C are moving relative to each other and have truly symmetrical worldlines. What stops B and C arguing about who is younger? I was hoping to do some calculations that showed the opposing clock doing strange (slow) things and finally catching up with 'mine' where I am either B or C, and then showing that the same happens if I am C or B....
When the triplets reunite, I'm hapy that B and C are the same age as each other and both younger than A, BUT: how does the clock of C look from B's perspective? This must be the same as how the clock of B looks from C's perspective, even though B and C are moving relative to each other and have truly symmetrical worldlines. What stops B and C arguing about who is younger? I was hoping to do some calculations that showed the opposing clock doing strange (slow) things and finally catching up with 'mine' where I am either B or C, and then showing that the same happens if I am C or B....