- #1
Magna1
- 17
- 0
I hate to ask for the answer on this one but the arguments are getting louder amongst us.
Here is the ??
A wire has a resistance of [tex]5\Omega[\tex]. It is melted down and drwan into a new wire of [tex]\frac{1}{2}]the original diameter. What is the resistance of the new wire?
Answer #1 [tex]5\Omega[\tex] because everything is proportional the amount of wire is the same just longer and not as thick.
Answer #2 This is where we want to get numbers for any kind of wire and plug them into the formula [tex]R=\frac{\rho*\ell}{A}. then hopefully see something that makes sense.
So our class is tomorrow and we can't settle on an answer. I hate to ask for the answer but we are out of time.
I tried to Latex but not sure how it will look.
I will repost if it doesn't make sense.
Thank You in Advance
Here is the ??
A wire has a resistance of [tex]5\Omega[\tex]. It is melted down and drwan into a new wire of [tex]\frac{1}{2}]the original diameter. What is the resistance of the new wire?
Answer #1 [tex]5\Omega[\tex] because everything is proportional the amount of wire is the same just longer and not as thick.
Answer #2 This is where we want to get numbers for any kind of wire and plug them into the formula [tex]R=\frac{\rho*\ell}{A}. then hopefully see something that makes sense.
So our class is tomorrow and we can't settle on an answer. I hate to ask for the answer but we are out of time.
I tried to Latex but not sure how it will look.
I will repost if it doesn't make sense.
Thank You in Advance