Period of the resulting SHM?

  • Thread starter brownniegyal
  • Start date
  • Tags
    Period Shm
In summary, a 3.00 kg cube with edge lengths d = 6.30 cm is mounted on an axle through its center. A spring with a spring constant of 950 N/m is attached from the upper corner of the cube to a rigid wall. When the cube is rotated 3.00° and released, it undergoes simple harmonic motion with a period that can be determined by converting the rotational motion into a distance the spring is stretched and using an approximate linear relation between the angle of rotation and the torque on the cube.
  • #1
brownniegyal
6
0
The 3.00 kg cube has edge lengths d = 6.30 cm and is mounted on an axle through its center. A spring (k = 950 N/m) connects the cube's upper corner to a rigid wall. Initially the spring is at its rest length. If the cube is rotated 3.00° and released, what is the period of the resulting SHM?

Please provide a solution rather than just an answer. I really appreciate any help:)
 
Physics news on Phys.org
  • #2
You are going to find that you won't get much of a response by just throwing questions into a template and posting them. You need to show that you've made at least some attempt at solving the problem on your own.
 
  • #3
what if i don't get it at all :(
 
  • #4
brownniegyal said:
what if i don't get it at all :(

Then you should probably start with a simpler question where you are only partially lost. For this problem convert the rotational motion of the cube into a distance the spring is stretched (a picture would really help here - I'm not sure what the geometry is). Then determine an approximate linear relation between the angle of rotation and the torque on the cube which, together with knowing the moment of inertial of the cube, gives you a SHO for small angular displacements.
 

What is the period of a Simple Harmonic Motion (SHM)?

The period of SHM is the time it takes for one complete cycle or oscillation of the motion. It is denoted by the symbol T and is measured in seconds.

How is the period of SHM calculated?

The period of SHM can be calculated using the formula T = 2π√(m/k), where m is the mass of the object in motion and k is the spring constant of the restoring force.

What factors affect the period of SHM?

The period of SHM is affected by the mass of the object, the spring constant, and the amplitude of the motion. A larger mass or a larger spring constant will result in a longer period, while a larger amplitude will result in a shorter period.

Can the period of SHM be changed?

Yes, the period of SHM can be changed by altering the factors that affect it, such as changing the mass or spring constant, or by changing the amplitude of the motion.

What is the relationship between frequency and period in SHM?

The frequency of SHM is the number of oscillations per unit time, and it is inversely proportional to the period. This means that as the frequency increases, the period decreases, and vice versa.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
27
Views
6K
  • Introductory Physics Homework Help
Replies
1
Views
885
  • Introductory Physics Homework Help
Replies
20
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
13
Views
4K
Replies
3
Views
2K
  • Introductory Physics Homework Help
2
Replies
37
Views
5K
Back
Top