- #1
grossgermany
- 53
- 0
Hi I've got a tough analysis proof. If I can do this on my own I might as well be Cantor himself.
The first step is :
Let C and N denote the collection of every cauchy sequence and null sequence (consisting of rationals) , prove that N is a subset of C
Second step is :
Prove N induces a equivalence relations on C.
The first step is :
Let C and N denote the collection of every cauchy sequence and null sequence (consisting of rationals) , prove that N is a subset of C
Second step is :
Prove N induces a equivalence relations on C.
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