In the first two diagrams, the normal force arrow is shown to the side just for clarity. (Otherwise it would be right on top of the weight force arrow.) There's no implication that the normal force actually acts off to the side.vin300 said:
Just under the diagram is this text:vin300 said:
Normal reaction in a rolling object refers to the force that a surface exerts on an object in contact with it, perpendicular to the surface. In the case of a rolling object, the normal reaction is the force that the surface exerts on the object to keep it from sinking into the surface.
The normal reaction and weight of a rolling object are directly proportional to each other. This means that as the weight of the object increases, the normal reaction also increases, and vice versa.
Normal reaction plays a crucial role in the motion of a rolling object. It helps to provide the necessary balance and stability for the object to move smoothly without slipping or sliding. It also helps to maintain the object's speed and direction of motion.
The normal reaction in a rolling object can be affected by various factors such as the weight and shape of the object, the type and condition of the surface it is rolling on, and the force or torque applied to the object.
The normal reaction in a rolling object can be calculated using the equation N = mgcosθ, where N is the normal reaction, m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of the surface with the horizontal plane.