- #1
DPXJube
- 12
- 0
Homework Statement
A person pushes a box across a horizontal floor with an initial velocity of 5.2m/s. The box has a mass of 22kg, and the coefficient of Kinetic friction between the box and the floor is 0.44. How far does the box slide before coming to rest?
Homework Equations
μk = FK/FN
Fnetx = FA - FK(assuming that right is positive and left is negative)
V2 - V1 = 2aΔd
The Attempt at a Solution
Rearrange μk = FK/FN to FK = μkFN
Find Normal Force
FN = FG
FG = mg
Get 215.6 for FG which is in turn the normal force.
FK = (0.44)(215.6)
FK = 94.9
Find acceleration
Fnet = FA - FK
ma = FA - FK
And at this point I do not know what to do as I do not have the apllied force.
The plan after that was to rearrange the Kinematic equation into Δd = V2-V1/2a and fill in for that.
Unless of course my Free Body Diagram is wrong and there IS no applied force, although that seems unlikely.