- #1
KataKoniK
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I am a bit confused here of whether the following functions diverge or converge.
[tex]\sum[/tex] [tex]\ln x \backslash x[/tex]
I used teh Integral test and got an answer showing the series is divergent where
Is this correct? I graphed the equation and saw an answer such that the equation converged to 0.
[tex]\sum[/tex] 2/(x (lnx)^2)
I don't think I did this right either. Using the integral test I got
So it converges to 2 / ln(2)
Am I allowed to assume that -2/(ln b) -> 0 as b-> infinity?
[tex]\sum[/tex] [tex]\ln x \backslash x[/tex]
I used teh Integral test and got an answer showing the series is divergent where
Code:
lim ((ln b)^2) / 2 = infinity
b-> infinity
Is this correct? I graphed the equation and saw an answer such that the equation converged to 0.
[tex]\sum[/tex] 2/(x (lnx)^2)
I don't think I did this right either. Using the integral test I got
Code:
lim -2/(ln b) + 2 / ln(2) = 2 / ln(2)
b-> infinity
Am I allowed to assume that -2/(ln b) -> 0 as b-> infinity?