- #1
phantomcow2
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Homework Statement
Find the length of the curve y=ln(cosx) from 0 to pi/3
Homework Equations
integral of (1+(y')^2)^1/2
The Attempt at a Solution
First, find y'. y' is equal to -sin/cos, or simply -tan(x).
[tex]\int[/tex][tex]\sqrt{1+(-tan(x)^{2}}[/tex]
= [tex]\int[/tex][tex]\sqrt{sec(x}[/tex]
Homework Statement
Can this possibly be right so far? This is a horrendous integral. I've expended so much energy on this problem, but if someone can at least validate that I am on the right track, I'll post my work from here out.