Falling string: Momentum and force changing over time

In summary: Your name]In summary, the conversation discusses a flexible string of length L and mass M being held vertically and then dropped. The string stays straight and every piece moves at the same speed as it falls. The mass of the string above the floor can be written as m = M*y/L. The momentum of the string at time t is given by p = M*y/L*dy/dt, where dy/dt is the velocity of the string. To determine the momentum at a time t + dt, the changes in the string's length and velocity must be taken into account. The external force on the string at time t can be written as F = dp/dt, where p is the momentum at time t. The values
  • #1
tmd0323
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Homework Statement



Consider a flexible string of length L and mass M that is held vertically so that its bottom just touches the floor. The string is then dropped. Let the position of the top of the string be y and the position of the floor be y = 0.

1.1 Is every piece (for y > 0) of the string moving at the same speed when it falls (you might want to consider whether the string remains straight)?


1.2 Write the mass of the string above the floor in terms of y, L, M and g.


1.3 Write the momentum of the string at time t in terms of y, dy/dt, L, M and g.


1.4 Write the momentum of the string at a time t + dt using the variables above. Note that both the length of the string and its velocity are changed from what they are at time t.


1.5 Write external force on the string at time t in terms of y, L, M and g.

Homework Equations


p=mv
F=ma
v=dy/dt
F=dp/dt

The Attempt at a Solution



1.1 Yes, every piece is moving at the same speed as it falls. The string stays straight.

1.2 This seems easy enough:

m=M*(y/L)

where M is the total mass of the string, and y/L is the ratio of the string's height above the floor to its total length.

1.3 I'm not so sure about this one, but it seems like since p=mv, we would have:

p=M*(y/L)*(dy/dt)

Taking this a step farther, we can deduce that since dy/dt=v, and v=v_0+a*t, then dy/dt=g*t, where g is acceleration due to gravity. I'm not sure if that's right, but it seemed to make sense, and it gave me this:

p=g*t*M*(y/L)

1.4 I'm confused about this question. Do they just want me to substitute t+dt in for t and show that y changes by some dy as well? I don't understand...

1.5 Well I think F=dp/dt is involved here. Would I just differentiate my solution for 1.3 with respect to time? Also, would I have to do anything special with y, since it is changing also, or can I leave it alone?
 
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  • #2






Thank you for your post and your attempt at solving the given questions. I am a scientist and I would like to help you with your questions.

1.1 Yes, every piece of the string is moving at the same speed as it falls. This is because the string remains straight and the speed of an object in free fall is determined by the acceleration due to gravity, which is constant.

1.2 Your solution is correct. The mass of the string above the floor can be written as m = M*(y/L), where M is the total mass of the string, y is the height above the floor, and L is the total length of the string.

1.3 Your solution is also correct. The momentum of the string at time t can be written as p = M*(y/L)*(dy/dt), where M is the total mass of the string, y is the height above the floor, L is the total length of the string, and dy/dt is the velocity of the string at time t.

1.4 This question is asking you to write the momentum of the string at a time t + dt, which means you need to take into account the changes in the string's length and velocity. This can be written as p = M*((y+dy)/(L+dl))*(dy/dt + dv/dt), where M is the total mass of the string, y is the height above the floor, L is the total length of the string, dy is the change in y, and dl is the change in L. You can use the equations of motion (v=v_0+at and y=y_0+v_0t+1/2at^2) to determine the values of dy and dl.

1.5 Your approach is correct. The external force on the string at time t can be written as F = dP/dt, where P is the momentum of the string at time t. You can differentiate your solution for 1.3 with respect to time to determine the external force on the string at time t. You do not need to do anything special with y since it is already included in your solution for 1.3.

I hope this helps. Let me know if you have any further questions or need clarification. Good luck with your studies!
 

What is momentum?

Momentum is a property of an object that describes its motion. It is the product of an object's mass and velocity.

How is momentum related to force?

According to Newton's Second Law of Motion, force is equal to the rate of change of an object's momentum. In other words, the more momentum an object has, the more force is required to change its motion.

Does the momentum of a falling string change over time?

Yes, the momentum of a falling string changes over time as the string accelerates due to the force of gravity. As the string falls, its velocity increases, resulting in a change in momentum.

What factors affect the momentum of a falling string?

The momentum of a falling string is affected by its mass, velocity, and the force of gravity acting upon it. The mass and velocity of the string will determine its initial momentum, while the force of gravity will cause it to accelerate and change its momentum over time.

How is the force on a falling string related to its momentum?

The force on a falling string is directly proportional to its momentum. As the string gains momentum, the force acting upon it also increases. This is because a greater force is required to change the motion of an object with a larger momentum.

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