Balancing Chemical Equations: Considering States of Reactants and Products

  • Thread starter campa
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In summary, the equation provided is 2NH3(s) + 3Cl2(g) -> N2(g) + 6HCl(g) and it is most likely referring to the gas phase reaction since NH3 is typically used as a water solution in labs. The state of NH3 in the first equation is gas, despite the potential misprint. The addition of extra Cl2 would result in the formation of NH4Cl(s) and H2(g). Chemical calculators such as BATE and CASC can be used for pH calculations, titration curves, concentration conversions, and solution preparation in lab and educational settings.
  • #1
campa
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2NH3(s) + 3Cl2(g) -> N2(g) + 6HCl(g)

What should the state of NH3 be?
 
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  • #2
NH3(s) ? What temperature are you working at ?
 
  • #4
Borek said:
At STP ammonia is a gas, although in lab practice it is most commonly used as a water solution.


Borek

Yeah, my thought was that he was talking about NH3(aq) (which is NH4OH), not the solid. Which of course produces (with Cl2(g)) NCl3 a moderate explosive. Hey haven't we all played with NI3 ... the stories I could tell ;)
 
Last edited:
  • #5
the equation was given to us like 2NH3(s) + 3Cl2(g) -> N2(g) + 6HCl(g) I'm not sure about the temperature though. And it also said that with extra Cl2 you get the equation like Cl2(g)+NH3(g) -> NCl3(g) + HCl(g)
I suppose the state of NH3 in the first equation must be gas. The teacher must have misprinted it!
 
  • #6
campa said:
the equation was given to us like 2NH3(s) + 3Cl2(g) -> N2(g) + 6HCl(g) I'm not sure about the temperature though. And it also said that with extra Cl2 you get the equation like Cl2(g)+NH3(g) -> NCl3(g) + HCl(g)
I suppose the state of NH3 in the first equation must be gas. The teacher must have misprinted it!

Close but one of the products from the gas phase reaction is NH4Cl(s).
 
  • #7
but I thought that you get NH4Cl(s) when you use extra NH3
 
  • #8
campa said:
but I thought that you get NH4Cl(s) when you use extra NH3

Another hint: H2(g).
 

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