- #1
Bailey
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can someone differentiate e^(nx) where n is any integer. i think is equal to n*e^(nx).
please show the proof, thanx.
please show the proof, thanx.
Originally posted by Bailey
thanx guys. i think the product rule can also use to differentiate
e^(nx), since e^(nx)=e^(n)*e^(x). but that will require much more time.
e^(nx)=e^(n)*e^(x).
It's mightily unnecessary as one term will automatically go to zero, and yes I missed his algebraic mistakeOriginally posted by futz
The product rule applies fine for a constant term, since a constant is a perfectly good function. It does not apply the way he said though; his exponential relation is wrong.
[tex]
e^ne^x=e^{n+x}
[/tex]
e^(nx) is an exponential function where the base is e and the exponent is multiplied by a constant, n. This is different from e^x, where the exponent is simply x. The value of e^(nx) will change depending on the value of n, while e^x will always be the same regardless of the value of x.
The derivative of e^(nx) can be found using the power rule and the chain rule. The derivative is n*e^(nx).
Yes, e^(nx) can be simplified using logarithms. For example, e^(2x) can be written as (e^x)^2. However, this may not always be necessary or helpful in solving a problem.
Exponential functions, such as e^(nx), are commonly used to model growth or decay in various natural phenomena such as population growth, radioactive decay, and compound interest.
Changing the value of n will affect the steepness of the graph of e^(nx). A larger value of n will result in a steeper graph, while a smaller value of n will result in a flatter graph. Additionally, if n is negative, the graph will be reflected over the x-axis.