Understanding AC Circuits: Questions About Light Bulbs and Complex Impedance

In summary, the frequency of AC current used in most countries is so fast that it is not perceptible to the human eye. Additionally, complex impedance and inductors/resistors in circuits can cause flicker, but this is minimised by the response of the eye/brain.
  • #1
NullSpace0
25
0
Recently, I've been studying AC circuits and have developed a couple questions. I think I worked out an answer to the first, but I don't know about the second.

First, since light bulbs in houses are powered by AC current, why do we not see them flicker? Assuming they obey Ohm's law, the current through them is in phase with voltage, and so it must be 0 twice every period. My guess is that 60 Hz or 50 Hz used in most countries is simply so fast that our eyes don't register the flicker?

Second, this question concerns complex impedance and inductors/ resistors in circuits. Let's say we have a variable inductor in series with a resistor. Supposedly this is an example of a light-dimmer, because if we increase the inductance, then there is a larger voltage drop across it because its reactance is jωL. What I don't understand is that since the voltage is AC, and the voltage across an inductor is L*dI/dt, wouldn't there be points in the cycle that the voltage across the inductor drops to 0, and then the voltage across the light bulb should increase a whole lot! So at least momentarily, why don't light bulbs change brightness oscillating between lighter and dimmer?

I guess that question also implies the question as to how impedance can be jωL (a constant) even though there are different voltage drops at different times across the inductor.

Thanks!
 
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  • #2
For 1. The filament in the bulb heats up, and it takes longer than 1/60th of a second to cool down again. The light it gives off depends on it's temperature - so it does not dim right away. You can see this when you switch off a very bright light (don't look at it) the illumination takes a short while to fade away. Lights that use other methods that respond faster to changes in current show an appreciable flicker.

For 2. You get the impedence from the relationship between voltage and current, not the voltage alone.
 
  • #3
It's important to realize that ωL is not equal to Vt/It, in which Vtand It are instantaneous values, but to Vrms/Irms (or to Vpeak/Ipeak).
 
  • #4
Simon has is. The filament has thermal mass which tends to smooth out the flicker to a significant extent. Likewise the response of the eye/brain also tends to mask flicker although some people are more sensitive than others.

The light output from an LED responds much faster to changing input so depending on how they are driven there can be more of a flicker problem with those. Perhaps worth a read..

http://www.digikey.com/us/en/techzone/lighting/resources/articles/characterizing-and-minimizing-led-flicker.html
 
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  • #5
1.A regular bulb lights up because inside the bulb, a thin wire called a filament gets very hot and glows. When the alternating current turns off for a fraction of a second, the filament does not cool off enough to stop glowing. That is why you cannot see the flicker with this kind of bulb.
 
  • #6
@Nullspace0: has that answered your question?
@Abhinav R: welcome to PF; good to see someone contributing.
 
  • #7
The frequency chosen for the mains supply was partly based upon the perception of flicker. It's right on the edge, actually, because the UK 50Hz is significantly worse than the US 60Hz.
Flourescent tubes are significantly worse than 'laggy' filament lamps. Did you know that they tend to use low voltage AC lighting in machine shops (with rotating machinery). This is because low voltage filaments (for the same wattage) have more massive filaments and their temperature varies less over the AC cycle. This reduces flicker and means there is less chance of rotating machinery appearing to be stationary due to strobing. It helps with accident prevention in noisy environments.
 

1. What is the purpose of a light bulb in an AC circuit?

In an AC circuit, the purpose of a light bulb is to convert electrical energy into light energy. As the alternating current flows through the filament of the light bulb, it heats up and emits light. This allows us to use electricity for lighting purposes.

2. How does the impedance of a light bulb affect the flow of current in an AC circuit?

The impedance of a light bulb, which is the overall resistance to the flow of current, affects the flow of current in an AC circuit by limiting the amount of current that can pass through it. As the impedance of the light bulb increases, the flow of current decreases, resulting in a dimmer light.

3. What is the relationship between voltage and current in a light bulb?

The relationship between voltage and current in a light bulb is described by Ohm's law, which states that the current through a conductor is directly proportional to the voltage and inversely proportional to the resistance. This means that as the voltage increases, the current through the light bulb also increases, resulting in a brighter light.

4. How do you calculate the complex impedance of a light bulb?

The complex impedance of a light bulb can be calculated using the formula Z = R + jX, where Z is the complex impedance, R is the resistance, and jX is the reactance. The reactance is determined by the frequency of the AC current and the inductance or capacitance of the light bulb.

5. Why is it important to understand complex impedance in AC circuits?

Understanding complex impedance is important in AC circuits because it allows us to accurately calculate and predict the behavior of the circuit. It also helps us to determine the most efficient components to use and ensure that the circuit is functioning properly. In the case of light bulbs, understanding complex impedance can help us to choose the appropriate wattage and type of bulb for the desired level of brightness.

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