Some help and explaination

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In summary, the conversation discusses a question about a stone being dropped from a height of 51.2 metres and the calculations needed to determine its time of descent, speed before impact, and distance fallen in the last second. The speaker also asks for help in understanding the question and solving the calculations.
  • #1
aussierad
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Hey guys,
Just wondering if you could please help me decode this question as well as put a little explanation as to how you got that answer. I am really struggling to get the correct calculations

(Take g = 9.8 m.s -2)

A stone is dropped from a height of 51.2 metres from the ground.
(a) How long does it take to reach the ground?
(b) What speed just before it strikes the ground?
(c) How far does it fall during the last second of it's fall?


Thanks!
 
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  • #2
  • #3


Hi there,

Sure, I'd be happy to help with decoding this question and providing an explanation for the calculations. First, let's break down the question and identify what information we have and what we are trying to find:

- We know that a stone is dropped from a height of 51.2 metres from the ground.
- The value of acceleration due to gravity, g, is given as 9.8 m/s^2.
- We are trying to find the following:
a) The time it takes for the stone to reach the ground.
b) The speed of the stone just before it strikes the ground.
c) The distance the stone falls during the last second of its fall.

Now, let's look at the formulas we can use to solve these questions:
- Time (t) can be calculated using the formula t = √(2h/g), where h is the initial height and g is the acceleration due to gravity.
- Velocity (v) can be calculated using the formula v = gt, where g is the acceleration due to gravity and t is the time.
- Distance (d) can be calculated using the formula d = (1/2)gt^2, where g is the acceleration due to gravity and t is the time.

To solve part (a), we plug in the values we have into the formula t = √(2h/g). In this case, h = 51.2 metres and g = 9.8 m/s^2. So, t = √(2*51.2/9.8) = √10.4 = 3.23 seconds. This is the time it takes for the stone to reach the ground.

For part (b), we can use the formula v = gt to calculate the velocity just before the stone strikes the ground. Again, we plug in the values we have, g = 9.8 m/s^2 and t = 3.23 seconds, and we get v = (9.8)(3.23) = 31.65 m/s. This is the speed of the stone just before it strikes the ground.

Finally, for part (c), we need to find the distance the stone falls during the last second of its fall. To do this, we need to find the distance it falls in the first 2.23 seconds (since we already know it takes 3.23 seconds to
 

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