Calculate the power of a the lift motor

In summary, to calculate the power of a lift motor that lifts a 400kg load 50m in 24 seconds, we need more data such as the speed of the lift, percentage of counterweighting, hoisting machine efficiency, acceleration rate, and hoistway efficiency. Using the given information, the power is estimated to be 8.175KW. However, additional factors may affect the actual power requirement.
  • #1
taomay
2
0
Please help :

Calculate the power of a the lift motor,when is lift on a distance on a building site lift 400kg of brick50m to the top of a buiding in 24 seconds

Ans ?

Regards.
taomay
 
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  • #2
You tell us.
 
  • #3
taomay said:
Please help :

Calculate the power of a the lift motor,when is lift on a distance on a building site lift 400kg of brick 50m to the top of a buiding in 24 seconds

Ans ?

Regards.
taomay
Ans :

mass= 400kg (convert mass to weight 1kg=9.81N (force of gravity on 1kg)

400x9.81=3924N
Workdone (j)= force xdistance
3924x50 =196200

Power = 196200 /24= 8175 W
convert to KW =8.175KW
 
  • #4
Assuming that this is a cable driven lift and not a hydraulic lift, more data is required to calculate the HP required to lift the load:
Desired speed of lift
% of counterweighting
Hoisting machine eff.
acceleration rate and rate of change of acceleration rate (known as jerk rate)
Hoistway eff.
H.P. required = Speed (fpm) x capacity (lbs) x Percentage of uncounterweighted load (usually .4 to .5 / 33000) / overall eff.*
* this can actually range anywhere from 40% to 90% depending upon machine be geared or gearless, the roping type usually being 1:1 or 2:1 as well as the types of guide shoes (roller or slide).
If steep accelleration and jerk rates are required to meet a specific performance than a larger motor maybe required to meet those peak torque requirements.
To convert HP to KW, multiply the HP times .746
 
  • #5


To calculate the power of the lift motor, we need to use the formula P = W/t, where P is power, W is the work done, and t is the time taken. In this scenario, the work done is the force required to lift the bricks (400kg) multiplied by the distance (50m). This gives us a total work of 20,000 joules (400kg x 50m).

Now, we need to convert the time taken into seconds, which is 24 seconds. Therefore, the power of the lift motor is 20,000 joules divided by 24 seconds, which gives us a power of approximately 833.33 watts.

It is important to note that this calculation does not take into account any friction or other factors that may impact the actual power required by the lift motor. This is a basic calculation that gives us an estimate of the power needed for the given scenario.
 

1. How is power calculated for a lift motor?

The power of a lift motor is calculated by multiplying the force applied by the motor with the speed at which it is applied. This can be expressed as P = F x v, where P is power, F is force, and v is velocity.

2. What units are used to measure power for a lift motor?

The units used to measure power for a lift motor are watts (W) or horsepower (hp). These units indicate the amount of work done per unit of time.

3. How do I determine the force applied by a lift motor?

The force applied by a lift motor can be determined by measuring the amount of weight the motor is able to lift. This can also be calculated by dividing the power output of the motor by its speed.

4. What factors affect the power of a lift motor?

The power of a lift motor can be affected by various factors such as the weight of the load, the efficiency of the motor, and the speed at which the motor is running. Other factors such as friction, resistance, and energy losses can also impact the power of a lift motor.

5. How can I increase the power of a lift motor?

The power of a lift motor can be increased by using a more powerful motor, reducing the weight of the load, and improving the efficiency of the motor. Regular maintenance and proper lubrication can also help to maintain the motor's power output. Additionally, using a pulley system or gearing can also increase the power of a lift motor.

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