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pikiche
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how would you calculate the work needed to evaporate water from washed clothes, if the clothes r in a well isolated room with temperature of 75F
help pleasezzz
help pleasezzz
edgepflow said:The energy required is the mass of water multiplied by the laten heat of vaporization:
Q = m [itex]h_{fg}[/itex]
Q = energy required
m = mass of water
[itex]h_{fg}[/itex] = latent heat of vaporization
If you want to estimate how long it will take to evaporate naturally, search for "swimming pool evaporation equation."
The sensible heat can be included as follows:phinds said:No, he said it starts off at 75 degrees. Surely that has to be taken into account. I mean, it CAN'T take the same amount of energy to evaporate water at 1 degree above freezing as to do it to water at 1 degree below boiling.
In this context, work is defined as the amount of energy required to change the state of water from liquid to gas, also known as evaporation.
The formula for calculating work needed to evaporate water is W = m * L, where W is the work in joules, m is the mass of water in kilograms, and L is the latent heat of vaporization in joules per kilogram.
The mass of water can be determined by measuring the volume of the water in milliliters and using the density of water, which is 1 g/mL, to convert to mass in kilograms.
The latent heat of vaporization for water is 2,260 joules per gram, or 2,260,000 joules per kilogram.
Yes, this calculation can be applied to other liquids as long as the specific latent heat of vaporization for that liquid is known.