|Jul27-12, 10:38 PM||#1|
Photoelectric effect and stopping potential
I have a question:
A stopping potential of 0.5 V is required when a phototube is illuminated with monochromatic light of 490nm wavelength. The wavelength of a different monochromatic illumination for which the stopping potential is 1.50V is closest to：
b) 330 nm
d) 400 nm
e) 500 nm
I am not very clear with the concept of this whole thing, so it will be nice if anyone can explain the concepts (or rather what are the fornulas) too. Thank you.
|Jul27-12, 10:42 PM||#2|
What can you tell us about the photoelectric effect? How does the energy of the incident photons affect the energy of the emitted electrons? What is the energy of a photon in terms of its wavelength?
There is a reason that we have a Homework Help Template here at the PF. It requires you to list the Relevant Equations...
|Jul27-12, 11:19 PM||#3|
I'm sorry I deleted the template... I thought that it was just the prompts...
This is what I know：
$E=frac(hc/lambda)$, which in this case equals to 4.0567E-19
then KE(max)=eV。=E-work function
(from what I understand V is the stopping potential)
Then, uhhhh. I start to confuse myself. I suppose that e in this case is the energy of an electron. I only have the formulas from powerpoint slides (for lessons that I didn't attend), but they are not very well explained.
Well, Thank you all.
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