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Radwa Kamal
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Homework Statement
A body of 2M(KG) mass at velocity V collided with a body of mass M(KG) at rest.
The first body after collision has a velocity ao 1/3V , and the second moves at 4/3V.
Verify both laws of conservation of linear momentum and energy with explanation.
Homework Equations
m1v1f + m2v2f= m1v1i+ m2v2i
KE = (1/2)mv^2
PE=mgh
The Attempt at a Solution
KE = (1/2)mv^2
KE before collision = 1/2 *2MV^2+ 1/2* M(0)=MV^2
KE after collision =1/2*2M(1/3V)^2+1/2*m(4/3V)^2=1/9MV62+8/9MV^2=MV^2
KE before collision=KE after collision
there is no height then there is no potential energy
(KE+PE) before collision + (KE+PE) after collision
then mechanical energy is constant at any point