- #1
jhaislip
- 3
- 0
Is anyone able to explain why someone wired this motor contactor circuit such that activating the coil is done by connecting the two leads to the following:
contactor: Allen-Bradley 69A86
lead 1: 120V AC
lead 2: 120V AC - Phase Shifted by 120 degrees
So I guess the difference of the two gives you an AC signal with amplitude of around 209V. But doesn't the contactor only need 120VAC across the coil to close? Why wouldn't they just have used 120VAC and neutral? In case more info is useful, the phase shifted 120VAC isn't used anywhere else in the circuitry although there is a chance it was used long ago with other motors/equipment which have since been removed. The 120VAC connected to lead 1 is also connected to the motor's L1 and L2 wires.
Thanks!
Josh
contactor: Allen-Bradley 69A86
lead 1: 120V AC
lead 2: 120V AC - Phase Shifted by 120 degrees
So I guess the difference of the two gives you an AC signal with amplitude of around 209V. But doesn't the contactor only need 120VAC across the coil to close? Why wouldn't they just have used 120VAC and neutral? In case more info is useful, the phase shifted 120VAC isn't used anywhere else in the circuitry although there is a chance it was used long ago with other motors/equipment which have since been removed. The 120VAC connected to lead 1 is also connected to the motor's L1 and L2 wires.
Thanks!
Josh