- #1
Mo
- 81
- 0
Ack! I thought i knew this!
"A car manufacturer test crash resistance by driving test vehicles off a horiztontal platform so that they fall to a concrete surface below.If this car is driven off at 20m/s and the platform is 15m above the ground calculate the impact angle and speed"
Im not to fussed about the impact angle just yet, i tried to work the speed out...
u = 0
a = 9.8
s (displacement) = 15
v = ?
t = ?
For this i need to use the equation: [tex]v^2 = u^2 + 2as[/tex]
[tex]v^2 = 2 \times 9.8 \times 15[/tex]
[tex]v^2 =294[/tex]
[tex]v = 17.15 m/s[/tex]
But the answer in the book is different, it says 26.3 m/s
Im most probably making an incredibly stupid mistake, please spot it!
thanks,
Regards,
Mo
"A car manufacturer test crash resistance by driving test vehicles off a horiztontal platform so that they fall to a concrete surface below.If this car is driven off at 20m/s and the platform is 15m above the ground calculate the impact angle and speed"
Im not to fussed about the impact angle just yet, i tried to work the speed out...
u = 0
a = 9.8
s (displacement) = 15
v = ?
t = ?
For this i need to use the equation: [tex]v^2 = u^2 + 2as[/tex]
[tex]v^2 = 2 \times 9.8 \times 15[/tex]
[tex]v^2 =294[/tex]
[tex]v = 17.15 m/s[/tex]
But the answer in the book is different, it says 26.3 m/s
Im most probably making an incredibly stupid mistake, please spot it!
thanks,
Regards,
Mo