Does entropy increase or decrease when black holes merge?

In summary, the entropy of a black hole increases when two black holes merge. The entropy change for the universe (in equivalent bits of information) when two solar mass black holes coalesce is unknown, but is presumably greater than zero.
  • #1
bon
559
0

Homework Statement



The Hawking/Bekenstein relation gives entropy S for a black hole as proportional to its area:

S = kc^3 / 4G hbar A

Does the entropy increase or decreatse when two black holes coalese into one?

What is the entropy change for the universe (in equivalent bits of information) when two solar mass black holes coalesce..?


Homework Equations





The Attempt at a Solution



Not sure what happens or how to work out entropy change..

What stays constant before and after? total mass?

Thanks
 
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  • #2
bon said:
Not sure what happens or how to work out entropy change..
What stays constant before and after? total mass?
Correct. When black-holes merge, you form a new black hole with a mass equal to the sum of the original black-holes. This is required from conservation of energy.
 
  • #3
Ok Thank you! It now asks me:

The internal energy of the black hole is given by the Einstein relation E= mc^2/ Find the temperature of the black hole in terms of its mass..

Im not sure how to do this..none of my equations contain temperature! How can i relate temperature to the energy of the black hole?

Thanks!
 
  • #4
They're (hopefully) referring to the temperature of http://en.wikipedia.org/wiki/Hawking_radiation" [Broken]. That article gives you the equation to find the temperature. Let me know if that doesn't make sense.
 
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  • #5
Ok thanks, but I don\'t think we are meant to use that because it\'s not given..I think we have to derive it somehow?

Also - still stuck on my previous question...

Does the entropy increase or decreatse when two black holes coalese into one?

What is the entropy change for the universe (in equivalent bits of information) when two solar mass black holes coalesce..?

So I see that the entropy will increase because A increases..and I can work out the entropy change..but what does it mean \"in equivalent bits of info\"? THanks!
 
  • #6
bon said:
Ok thanks, but I don\'t think we are meant to use that because it\'s not given..I think we have to derive it somehow?
You definitely don't need to derive the equation for hawking radiation. I can't think of any other temperature they might be referring to...

bon said:
So I see that the entropy will increase because A increases..and I can work out the entropy change..but what does it mean \"in equivalent bits of info\"? THanks!
Great. 'in bits' just means using a particular unit of measurement of entropy. I'm not sure if you're familiar with any computer-science, but its the same 'bit'---referring to a single piece of information (yes or no; 0 or 1). You'd have to check your formula to see what units its in---I'm not sure off hand. I'm sure google could find out.
 
  • #7
OK i see now. Thanks. I\'m trying to do the bit that says: find the temp of a black hole in terms of its mass.

Surely you can use the first law: dU = Tds - pdV

this implies T = dU/dS at const. Vol

What i don't understnad is how this can be:

U = mc^2 so we are left with dm/DS at const V. But how can S change at const V if S = kA where A is area. If Vol is fixed, so is area, thus so is volume?

THanks!
 
  • #8
zhermes said:
You definitely don\'t need to derive the equation for hawking radiation. I can\'t think of any other temperature they might be referring to...


Great. \'in bits\' just means using a particular unit of measurement of entropy. I\'m not sure if you\'re familiar with any computer-science, but its the same \'bit\'---referring to a single piece of information (yes or no; 0 or 1). You\'d have to check your formula to see what units its in---I\'m not sure off hand. I\'m sure google could find out.

Hey. Just thought I\'d quote you so you see my reply.. thanks.
 
  • #9
bon said:
Surely you can use the first law: dU = Tds - pdV
this implies T = dU/dS at const. Vol
...
But how can S change at const V if S = kA where A is area. If Vol is fixed, so is area, thus so is volume?
I'm not sure if that will work (honestly I kind of doubt it), but its a good exercise either way.

You can't treat either the Volume or the Area as a constant (because they're not). You have an expression for the entropy, the volume, the potential energy, and you're looking for the temperature. You also need an expression for the pressure---the only option would be gravitational.

Give it a try, let me know what you get!
 

1. What is a black hole?

A black hole is a region of space where the gravitational pull is so strong that nothing, including light, can escape from it. It is formed when a massive star collapses under its own gravity.

2. How does temperature relate to black holes?

Black holes have a temperature, known as the Hawking temperature, which is inversely proportional to their mass. This means that smaller black holes have a higher temperature than larger ones.

3. What is the relationship between black holes and entropy?

Black holes have an entropy, which is a measure of the disorder or randomness of a system. The entropy of a black hole is directly proportional to its surface area, meaning that as a black hole grows, its entropy also increases.

4. Can black holes emit radiation?

Yes, black holes can emit radiation known as Hawking radiation. This is a result of quantum effects near the event horizon, where particles and antiparticles can be created and one falls into the black hole while the other escapes as radiation.

5. What is the significance of black hole thermodynamics?

Black hole thermodynamics is significant because it helps us understand the behavior of black holes and their connection to fundamental laws of physics, such as the laws of thermodynamics. It also provides insight into the nature of gravity and the role of entropy in the universe.

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