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jrjack
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Homework Statement
The full problem is y=e^(x/2) and y=e^(-x) revolved around the x-axis, from [ln6,ln12].
The part I'm struggling with is evaluating 2e^(ln12/2) and 2e^(ln6/2).
I am just reviewing for my Calculus 1 final.
Homework Equations
The Attempt at a Solution
[tex]2e^{(ln12/2)}[/tex]
[tex]2 e^{(1/2)(ln12)}[/tex]
[tex]2 (e^{1/2}), e^{ln12}=12, and 2(12)e^{1/2}?[/tex]