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AbsoluteZer0
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Homework Statement
250.0g of copper at 100.0°C are placed in a cup containing 325.0g of water at 20.0°C. Assume no heat loss to the surroundings. What is the final temperature of the copper and water?
Homework Equations
Conservation of Energy
mcCΔTc = mhCΔTh
The Attempt at a Solution
mcCΔTc = mhCΔTh
(0.250)(390)(Tf - Ti) = (0.325)(4200)(Tf - Ti)
(0.250)(390)(Tf - 100) = (0.325)(4200)(Tf - 20)
Have I set up my equation properly?