- #1
kq6up
- 368
- 13
Just for kicks. I tried calculating Keq from Gibb's free energy. This should be a straight forward calculation, but the answer is no where near close.
Here is my calculations in SAGE:
sage: R=8.314; T=298; G=237000 ; Keq=var('Keq'); f=G+R*T*log(Keq)
sage: f.solve(Keq)
[Keq == e^(-59250000/619393)]
sage: float(e^(-59250000/619393))
2.8588096844432612e-42
Note the positive sign before R, that is because when I solve for Keq sage assumes f=0.
I assume using the -(G) should give the self dissociation constant for water. That is 10^(-14)
Thanks,
Chris Maness
Here is my calculations in SAGE:
sage: R=8.314; T=298; G=237000 ; Keq=var('Keq'); f=G+R*T*log(Keq)
sage: f.solve(Keq)
[Keq == e^(-59250000/619393)]
sage: float(e^(-59250000/619393))
2.8588096844432612e-42
Note the positive sign before R, that is because when I solve for Keq sage assumes f=0.
I assume using the -(G) should give the self dissociation constant for water. That is 10^(-14)
Thanks,
Chris Maness