- #1
nil1996
- 301
- 7
let Rg be the resistance of the galavanometer.
A formula in my book states that
V=Ig(Rg+R)
my doubt is:
here Ig(Rg+R) is the potential drop across the two resistors of the voltmeter.
But how can this include the potential drop by the circuit element across which the voltmeter is connected.