DDWFTTW Turntable Test: 5 Min Video - Is It Conclusive?

In summary, this turntable and cart seem to be able to move faster than the wind, but it's not conclusive proof of DDWFTTW. There are some possible explanations for the effect, including lift.
  • #981
swerdna said:
It’s so unbalanced I think any mechanical heterodyne vibrations should be well and truly nullified.

Cool - a mechanical superheterodyne!
 
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  • #982
swerdna said:
Here’s a video of a crude, smaller, tiered TT to change the relative speeds. It was put together very quickly so “never mind the quality, feel the width”. It shows you don’t need to build a big TT to observe the effect. It’s so unbalanced I think any mechanical heterodyne vibrations should be well and truly nullified.



The Vice Grips is the source of the power:biggrin:
 
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  • #983
Subductionzon said:
The Vice Grips is the source of the power:biggrin:

Close - It’s the fairy dust sprinkled on the vice grips.
 
  • #984
A smaller cart wheel (5.5cm dia). Sorry about the background glare and the now unbalanced TT (stupid tiered demo).

 
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  • #985
swerdna said:
A smaller cart wheel (5.5cm dia). Sorry about the background glare and the now unbalanced TT (stupid tiered demo).



~1.3x the wind - which of course again perfectly demonstrates schroder's theory. (Well, as long as you incorporate the square root of the average frequency played by the woodwind section during Beethoven's Fifth into the Fourier transform.) :biggrin:

JB
 
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  • #986
swerdna said:
Here’s a video of a crude, smaller, tiered TT to change the relative speeds. It was put together very quickly so “never mind the quality, feel the width”. It shows you don’t need to build a big TT to observe the effect. It’s so unbalanced I think any mechanical heterodyne vibrations should be well and truly nullified.



And this one 1.2x the wind speed -- also "exactly what schroder would expect".

JB
 
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  • #987
ThinAirDesign said:
~1.3x the wind - which of course again perfectly demonstrates schroder's theory. (Well, as long as you incorporate the square root of the average frequency played by the woodwind section during Beethoven's Fifth into the Fourier transform.) :biggrin:

JB


First of all, it's not ~1.3x the wind. It's 1.2939405837488622221102739591383X the wind.

Second, you're just being silly. This has nothing to do with woodwinds.

Consider this: sqrt(sqrt(1.41)) = 1.08969

and 1.08969 * 1.29394058374886 = 1.41 - The first Bessel null!

You see!? It's science. And in the immortal words of John Cleese... "it's perfectly simple"
 
  • #988
ThinAirDesign said:
And this one 1.2x the wind speed -- also "exactly what schroder would expect".

Again you're being sloppy. It's not 1.2x - but rather 1.18743420870379172346729176X. Your measurement is off by more than 1%

This is simply the sqrt of 1.41 - the first Bessel Minor!

Now don't make me get into the hyperbolic cosine of the catenary function of the 3rd Bessel Major in the complex plain - you wouldn't like it.
 
  • #989
swerdna said:
Not sure if it was just more “run in” or because I re-washed the bearings but the cart is running more efficiently in this video -

In the first video it takes about one and a third revolutions of the cart before it “hovers” while in the second video it takes less than one revolution. You should find the TT speed is the same in both videos. The terminal speed in the second also seems much faster to me but I haven‘t measured it.



And this one ~1.6x the wind speed. And of course given the carefully controlled circumstances, this is precisely what schroder would have predicted from his mechanical heterodyne.

JB
 
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  • #990
ThinAirDesign said:
And this one ~1.6x the wind speed. And of course given the carefully controlled circumstances, this is precisely what schroder would have predicted from his mechanical heterodyne.

Again, you're being sloppy with your measurements. The actual speed in this case was 1.622X (you're off by 1.3%)

I think you'll see that when we divide the first Bessel Null by the tangent of the First Bessel Null mantissa (normalized) we get precisely the speed found in this experiment. This represents the trigonometric 2nd Bessel eigenvalue.

1.41/tan(41) = 1.622
 
  • #991
So, let's review:

We have videos showing DDWFTTW devices going ~ :

1.01x
1.03x
1.2x
1.3x
1.4x
1.6x

... all of which absolutely confirm schroder's mechanical heterodyne and are exactly what he would have expected.

He just may be onto something here guys. :rolleyes:

JB
 
  • #992
schroder said:
.. Saying that you can extract energy from the headwind, in order to move against the headwind, is nonsense. ...
No this is common experience, as sailors have been doing it crudely starting ~2000 years ago with manipulations of the square sail, and doing it efficiently now for ~300 years. You agreed to this months ago BTW. To correct your counter factual: many kinds of wind powered craft, e.g. sailboats (water/ice), gliders, extract energy from the wind stream while moving against the wind.. As was pointed out months ago, ice sail boats commonly attain speeds of 4x the wind speed while moving up wind, and RF gliders have been clocked at hundreds of miles per hour in common ground winds.

Edit: #992!
 
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  • #993
tsig said:
Just take it outside in the wind see if it moves,

We've done this Tsig and we've posted the videos -- and you know this.

Why do you not want to test it in the wind?

Why do you want to tell lies?

JB
 
  • #994
schroder said:
Because, spork, you have it all wrong! The way I see it, the original “inventor” of this cart did it as a joke, a spoof, and he himself admitted that it will not work. The original outdoor video is a hoax, as the propeller is turning as a wind turbine. The only chance to see the actual direction of the propeller turning comes right at the end of the video, when the cart slows down. It would be hard to doctor the video at that point, and have the propeller reverse direction, so they did the next best thing; have the cart go off camera until it is stopped, and then pan back on it showing the prop spinning as a prop! It is so obviously a hoax that it really is a joke! The reason why I am interested is because of what is happening on the turntable.

Ok this really takes the cake. Are you just straight out lying or do you really expect us to believe that you don't understand the "strobe" effect of low frame rate movies (as per the old wagon wheels appear to turn backwards on movie films etc).

Here's the original outdooor test that Schroder is referring to.


Note that the device will be acting as a propeller if it turns counter-clockwise looking from behind and that it will be acting as a wind turbine if it turns clockwise when looking from behind. You can very clearly see that it turns counter-clockwise (from behind) when it is running very slowly, both at the start and at the end of the video. Now Schroder is telling us that this prop is actually rotating clockwise (from behind) because it appears to turn this way due to strobe effect at about 2.55 in the video. If you watch the whole video you can clearly see that it appears to change rotation direction many times throughout the clip, obviously due to strobe effect at different speeds.

Is there anyone else here that's seriously in doubt about the direction of rotation here (counter-CW from behind), or is this just another instance of Schroder being unbelievably silly?
 
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  • #995
It's pretty obvious that schroder has a hard time understanding what he sees. The prop turns CCW as seen from behind, the opposite of what he says. It is not a wind turbine.
 
  • #996
schroder said:
Once the cart (if ever) exceeds the velocity of the wind, it is going against a headwind!
Apparent headwind. The wind speed versus ground speed is still being slowed by the prop wash, because the prop accelerates the apparent headwind to a faster still upwind speed, which opposes the true wind, slowing the true wind down, the same as any wind powered device.

Saying that you can extract energy from the headwind
But that isn't what's happening. The energy for the cart is extracted from the true tailwind by slowing it down (true wind speed = (wind_speed - ground_speed). The headwind is an overhead, but not enough to prevent the prop from being able to generate thrust efficiently enough to slow down the wind while still moving DDWFTTW.

extract energy from the force of the propeller, to drive the propeller
The DDWFTTW carts function because they interact with air and ground that are moving at different speeds.

Using the cart as the frame of reference here: the prop generates thrust the same as any prop, force = (air mass flow) x (Vout - Vin). Power output = prop thrust times air speed through the prop. Power input = prop thrust times ground speed, and since ground speed > air speed, power input is > power output, with enough power input left over to drive the prop to generate the thrust, and overcome all the losses in the power conversion to the prop and the rolling and aerodynamic drag factors on the cart.

There's no magical transition at wind speed, since propellers normally operate in an apparent headwind. The limiting factor is overall efficiency. If the overall efficiency if 50%, then power output is 50% of power input, so the apparent headwind would have to be 50% of the "apparent" ground speed (since thrust is the same for interaction with air and ground). This would be good enough for double the wind speed, a 10 mph true wind, for a cart moving at 20mph downwind, from the cart's frame of reference translates into 10 mph apparent headwind, 20 mph apparent ground speed.

The fastest cart so far is only going 1.6 times wind speed, say 16 mph in a 10 mph wind. From the cart's frame of reference, apparent headwind = 6 mph, apparent ground speed = 16 mph, an overall efficiency factor of a paltry 37.5%.
 
  • #997
schroder said:
Saying that you can extract energy from the headwind, in order to move against the headwind, is nonsense.
Correct. These carts extract energy from the tailwind by slowing it down. The headwind is an overhead, as explained in my previous post, but doesn't prevent DDWFTTW.

extract energy from the headwind
mheslep said:
No this is common experience ... sailcraft ...
No sailcraft extracts energy from an apparent headwind (except when it's using the wind to decelerate the sailcraft). A sailcraft extracts energy from an apparent tailwind or apparent crosswind. The highest speeds are achieved when a sailcraft extracts energy from an apparent crosswind. Note the apparent crosswind is independent of the sailcrafts speed (by definition, it's perpendicular to the path of the sailcraft), and is equal to the true wind (wind_speed - ground_speed) times sin(angle between wind and direction of sailcraft). The maximum speed of the sailcraft depends on how much apparent headwind and ground related drag the sailcraft can achieve for a given apparent crosswind.
 
  • #998
Jeff Reid said:
No sailcraft extracts energy from an apparent headwind (except when it's using the wind to decelerate the sailcraft). A sailcraft extracts energy from an apparent tailwind or apparent crosswind.

My goodness Jeff ... got to call you on this one.

Unless you define "apparent headwind" as *only* coming from directly ahead you are wrong. Also, if you were to use that definition you would also have to use the term "apparent crosswind" *only* when the wind is coming from 90d cross, and "apparent tailwind" as that wind coming *only* from directly behind. Any other usage would be inconsistent.

Obviously you are trying to use "crosswind" and "downwind" in one broad form and then restricting "headwind" to another very restrictive form. Bad form.

Other than spinnaker (DDW) work, sailcraft are all extracting energy from some form of apparent crosswind -- depending on the the speed of the boat, etc., that crosswind may either have a headwind or tailwind component.

Sailcraft have for many centuries extracted energy from this apparent headwind. The DDWFTTW cart does it as well.

JB
 
  • #999
Jeff Reid said:
No sailcraft extracts energy from an apparent headwind (except when it's using the wind to decelerate the sailcraft). A sailcraft extracts energy from an apparent tailwind or apparent crosswind.

ThinAirDesign said:
Unless you define "apparent headwind" as only coming from directly ahead ... Also, if you were to use that definition you would also have to use the term "apparent crosswind" only when the wind is coming from 90d cross.
Which is exactly what I meant. I separate the apparent wind into components in the direction of and perpendicular to the direction of the sailcraft (wrt to the ground). The component in the direction of sailcraft is an apparent headwind or apparent tailwind (or zero). The component perpendicular to the sailcraft is an apparent crosswind (or zero).

Separating the apparent wind into apparent headwind and crosswind components makes sailcraft math easier as shown in this post:

https://www.physicsforums.com/showthread.php?p=2044882#post2044882

extracted energy from this apparent headwind. The DDWFTTW cart does it as well.
DDWFTTW carts extract energy from the apparent ground speed (times thrust, to drive the prop), not the apparent headwind. The apparent headwind is an overhead. The force from the ground that drives the prop is also opposing the carts forward motion, so it's a power input and at the same time an overhead in the system that must be overcome by higher thrust (at slower air speed) at the prop.

Upwind carts extract energy from an apparent headwind, but not downwind carts.

An upwind cart, (advance ratio > 1) extracts energy from an apparent headwind, by decelerating it, which also decelerates the true wind. This is a bit confusing because the cart is designed so the rate of true wind deceleration is less when the cart advances against the wind.

A DDWFTTW cart (0 < advance ratio < 1) has to accelerate an apparent headwind in the upwind direction in order to decelerate the true wind. For a DDWFTTW cart, the apparent headwind is an overhead.

Upwind and downwind carts, and wind powered (wind speed differing from ground speed) devices in general, decelerate the wind (relative to ground) in order to extract power from the wind. Both both upwind and downwind carts operate "best" when power consumed versus speed achieved is minimized.
 
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  • #1,000
Jeff Reid said:
...No sailcraft extracts energy from an apparent headwind (except when it's using the wind to decelerate the sailcraft). A sailcraft extracts energy from an apparent tailwind or apparent crosswind. The highest speeds are achieved when a sailcraft extracts energy from an apparent crosswind. Note the apparent crosswind is independent of the sailcrafts speed (by definition, it's perpendicular to the path of the sailcraft), and is equal to the true wind (wind_speed - ground_speed) times sin(angle between wind and direction of sailcraft). The maximum speed of the sailcraft depends on how much apparent headwind and ground related drag the sailcraft can achieve for a given apparent crosswind.
:confused: Perhaps a clarification of terms? All we're really talking about here is the work done by an airfoil, in this case a sail based airfoil. The sail will generate lift above any angle that does not 'back' the sail, typically from 20 degrees off the wind all the way up to the stall angle. The sail airfoil will generate lift from a vessel dead stop from a wind stream at any angle above the backing angle, do work and accelerate the craft over the surface. As the craft accelerates the apparent wind speed does indeed increase and the apparent wind direction moves toward the bow.

Example:
Sailcraft headed 'upwind'. Say: 30 degrees off the bow at 10kn. Craft dead stop. The component of the wind directly on the nose, or direct headwind, is 8.67kn. The craft is allowed to accelerate along its axis, and by common experience it will certainly do so absent restraint. The craft is allowed to reach, say, 5kn relative the surface. Now the apparent wind magnitude is 14.5kn at an angle 20deg off the bow. The head wind, direct on the nose component has risen to 13.7kn.

Maybe a wiki airfoil picture is helpful:
http://upload.wikimedia.org/wikipedia/en/2/2d/Equal_transit-time_NASA_wrong1.gif [Broken]
The axis of the craft can be only few degrees (~15) off the from the airfoil chord here, so that the lift vector has a component parallel to the axis of the craft.

Perhaps you meant that the craft would fail to do work if it were rigged so that its sail foil chord is aligned with the vessel axis in such a way that the lift vector is perpendicular to the vessel, and it that case I of course agree no net force is exerted along the vessel axis.
 
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  • #1,001
You need to avoid using sources with "longer path" or "equal transit" theory, if you want to talk about how lift is generated and be taken seriously.

Aside from the fact that the "equal transit" theory is complete nonsense, the image shown has the stagnation point entirely in the wrong location.
 
  • #1,002
Jeff, I'm pretty sure that we both have the same understanding regarding how a sail works and are just discussing semantics, but again I just have to repeat ... your statement:

No sailcraft extracts energy from an apparent headwind

... is just plain wrong.

The "sailcraft" is the entire system, not just the sail -- and inarguably (rationally at least) sailcraft CAN and DO extract energy from headwinds, apparent and true.

Perhaps you wish to argue that when analyizing a specific component of the sailcraft (like perhaps the sail) there is a different conclusion, and I'll have to think about that before responding -- but the "sailcraft" wording just doesn't fly.

JB
 
  • #1,003
Yes!

1002 reached ! Brilliant. You guys have been great. With a special thanks to Schroder :smile:
 
  • #1,004
mheslep said:
Perhaps a clarification of terms?
I did that in post #999 (congrats on having the 1000th post). I separate the apparent wind into components in the direction of and perpendicular to the direction of the sailcraft (wrt to the ground). The component in the direction of sailcraft is an apparent headwind or apparent tailwind (or zero). The component perpendicular to the sailcraft is an apparent crosswind (or zero).

work done by an airfoil, in this case a sail based airfoil. The sail will generate lift.
I prefer to separate the components with respect to the direction of the sailcraft. In this case, the purpose of a sail is to generate thrust (wrt to sailcraft). The "lift" component (wrt to sailcraft) only results in an equal and opposing force from the ground. It doesn't directly contribute to the forward speed of the sailcraft. If a sailcraft experiences an apparent headwind, then the thrust from the sail is related to the apparent crosswind, not the apparent headwind. The sail also needs to divert (accelerate) the apparent wind (both headwind and crosswind components) to true upwind sufficiently so that the true wind (wrt to ground) is decelerated.

Maybe a wiki airfoil picture is helpful:

Equal_transit-time_NASA_wrong1.gif

There's a reason that diagram is named "wrong". It's sufficient to note that the pressure "above" an airfoil is less than the pressure "below" in order to generate lift (how it does this can be a discussion in another thread). In the case of a sailcraft, "lift" from an airfoil, wrt to the apparent wind, isn't interesting, only the component of "lift" that translates into thrust wrt to the sailcraft.

Perhaps you meant that the craft would fail to do work ... lift vector is perpendicular to the vessel.
This is a case of my terminology, not the physics of the airfoil. I should have made myself more clear. I tried to cover this in post #999.
 
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  • #1,005
Jeff Reid said:
I prefer to separate the components with respect to the direction of the sailcraft...

Let's consider a direct-upwind prop-cart. This would be basically the same as our DDWFTTW cart only we change the gearing so it will advance directly into the wind. This "sailcraft" will in fact use an apparent (and true) headwind to propel itself directly upwind. Of course the blades of the prop are not going directly upwind (nor directly into an apparent headwind), but as JB says we're talking about the sailcraft - not the sail.


No sailcraft extracts energy from an apparent headwind

I tend to agree with JB that this probably has more to do with semantics than physics, but I still struggle with this statement because we definitely feel a very significant effect of apparent wind while kiteboarding. When going 90 degrees to the true wind the pull of the kite and performance overall definitely improves as our speed increases. Clearly the only thing changing in such a situation is that the apparent headwind is increasing (working from your definition), yet we definitely seem to extract energy from it.
 
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  • #1,006
swerdna said:
Good to see you’re still “with us”. Don’t see how two videos where everything is the same except the efficiency of the cart can give the same mathematical results when the observed results are so different.

Wheel running Radius of TT = 60cm. Wheel diameter = 8cm.

Thanks for that. I will do a few calculations and let you know what I find.
 
  • #1,007
swerdna said:
A smaller cart wheel (5.5cm dia). Sorry about the background glare and the now unbalanced TT (stupid tiered demo).



The bouncing around is sure to have an effect on the drop out and it certainly does. However, the longer it runs, the faster the cart is going. Right at the end I had the cart going from 8 o’clock to 3 o’clock CCW or a displacement of 5 hours for one CW revolution of the TT. That is 2.4 : 1
 
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  • #1,008
Jeff Reid said:
No sailcraft extracts energy from an apparent headwind.
spork said:
Let's consider a direct-upwind prop-cart.
I already did.
Jeff Reid said:
Upwind carts extract energy from an apparent headwind, but not downwind carts.
I wasn't considering an upwind cart as a sailcraft. If an upwind cart is to be considered as sailcraft, then upwind sailcraft are the exception to the rule.

The main point I was getting at is that the true wind has to be decelerated (wrt ground) in order to extract power from the wind. For a downwind cart, an apparent headwind has to be accelerated upwind, reducing thrust from the propeller, and increasing drag; the apparent headwind is an overhead for a downwind cart, not a source of energy.

Of course the blades of the prop are not going directly upwind
Sails on a front to back track on the cart could be used instead, with no crosswind component required, just movement of the sails relative to the cart. Slower backwards relative to cart speed for a downwind cart, faster backwards for an upwind cart. (The sails would retract and redeploy at the ends of the track, sort of a linear like paddle wheel).

I still struggle with this statement (sailcraft don't extract energy from a headwind) because we definitely feel a very significant effect of apparent wind while kiteboarding. When going 90 degrees to the true wind the pull of the kite and performance overall definitely improves as our speed increases. Clearly the only thing changing in such a situation is that the apparent headwind is increasing (working from your definition), yet we definitely seem to extract energy from it.
The pull will get stronger, but only in the direction perpendicular to travel. The thrust will diminish as speed increases.

Perhaps I should restate what I'm getting at: The apparent headwind component of the apparent wind on an airfoil results in lift and drag. Only the apparent perpendicular component of the apparent wind on an airfoil can result in thrust.

Where the apparent headwind comes into play is that the sail diverts the apparent wind, both headwind and crosswind, with a signifcant true upwind component, decelerating the true wind, even though the sailcraft's downwind component of speed is faster than the wind.
 
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  • #1,009
uart said:
Ok this really takes the cake. Are you just straight out lying or do you really expect us to believe that you don't understand the "strobe" effect of low frame rate movies (as per the old wagon wheels appear to turn backwards on movie films etc).

Here's the original outdooor test that Schroder is referring to.


Note that the device will be acting as a propeller if it turns counter-clockwise looking from behind and that it will be acting as a wind turbine if it turns clockwise when looking from behind. You can very clearly see that it turns counter-clockwise (from behind) when it is running very slowly, both at the start and at the end of the video. Now Schroder is telling us that this prop is actually rotating clockwise (from behind) because it appears to turn this way due to strobe effect at about 2.55 in the video. If you watch the whole video you can clearly see that it appears to change rotation direction many times throughout the clip, obviously due to strobe effect at different speeds.

Is there anyone else here that's seriously in doubt about the direction of rotation here (counter-CW from behind), or is this just another instance of Schroder being unbelievably silly?


By all means please carefully watch that video. Wait with great patience towards the end to see which way the propeller is turning. Don’t get caught reaching for the popcorn at the moment of truth when the prop is slow enough to just see…..OH crap! What happened there? The cart goes off camera! How strange is that anyway? Right at the very point where we can see the direction of rotation! Accident or hoax? You be the judge. And if you believe this video, I have a bridge for sale in Brooklyn, very good price special for you!
 
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  • #1,010
Jeff Reid said:
The fastest cart so far is only going 1.6 times wind speed, say 16 mph in a 10 mph wind. From the cart's frame of reference, apparent headwind = 6 mph, apparent ground speed = 16 mph, an overall efficiency factor of a paltry 37.5%.

Do you have any evidence for this? The best I have seen is Swerdna’s turntable during the heterodyne run with a ratio of 2.4 : 1 which equates to 1.41 x turntable velocity. And I stress 1.41 x Turntable velocity, NOT wind velocity! In the wind, I have seen exactly Zero evidence of anything greater than wind velocity.
 
  • #1,011
Jeff Reid said:
Correct. These carts extract energy from the tailwind by slowing it down. The headwind is an overhead, as explained in my previous post, but doesn't prevent DDWFTTW.



No sailcraft extracts energy from an apparent headwind (except when it's using the wind to decelerate the sailcraft). A sailcraft extracts energy from an apparent tailwind or apparent crosswind. The highest speeds are achieved when a sailcraft extracts energy from an apparent crosswind. Note the apparent crosswind is independent of the sailcrafts speed (by definition, it's perpendicular to the path of the sailcraft), and is equal to the true wind (wind_speed - ground_speed) times sin(angle between wind and direction of sailcraft). The maximum speed of the sailcraft depends on how much apparent headwind and ground related drag the sailcraft can achieve for a given apparent crosswind.


Agreed. After going DIRECTLY downwind, if ever the craft exceeds wind velocity, it will be going Directly upwind! Going Directly upwind there is no crosswind, it is the same as going downwind again, in REVERSE! Going directly upwind means the craft is at the same angle to the wind as the angle of the wind to the water. The sine of zero is zero, meaning you have no crosswind component. The craft would be pushed backwards. All the talk of tacking at an angle is not relevant to this discussion. Let us please leave sailboats and iceboats that are tacking at an angle, out of this discussion.
 
  • #1,012
vanesch said:
Yes!

1002 reached ! Brilliant. You guys have been great. With a special thanks to Schroder :smile:

It's always nice to be appreciated! But this thread can stop as soon as you admit to the following:

1) There is NO evidence at all that any cart has ever or will ever go directly down wind faster than the wind.

2) That what is happeneing on the turntable, while interesting, has NO relationship to what happens in the wind.
 
  • #1,013
schroder said:
no crosswind component.
The DDWFTTW carts don't need a crosswind component.

If the craft exceeds wind velocity, it will be going directly upwind!
For DDWFTTW carts, the only thing that has to move slower than wind speed is the air from the prop wash. The craft will experience an apparent headwind, but the prop will be accelering the apparent headwind faster still, so that the prop wash still opposes the true wind, slowing the true wind down as required for any wind powered device.

As mentioned before once at terminal speed, power output related to thrust = thrust times apparent headwind (wrt cart), and is less than power input = thrust time apparent ground speed (wrt cart). The rest of the power ends up as heat.

The thrust is related to the change in speed of the true wind, with the prop acting as any prop, where thrust = (mass flow / unit time) x (Vout - Vin). As long as Vin, the apparent headwind, doesn't exceed the capabilities and efficiency of the cart and it's prop, the cart can go DDWFTTW.
 
  • #1,014
schroder said:
OH crap! What happened there? The cart goes off camera! How strange is that anyway? Right at the very point where we can see the direction of rotation! Accident or hoax? You be the judge.

O.K. I will be the judge. The prop is geared direclty to the drive shaft via a timing belt with a 90 degree twist. There is NO WAY for it to change directions. Why not watch the beginning of the video where this is abundantly clear!?

And if you believe this video, I have a bridge for sale in Brooklyn, very good price special for you!

I've built my own carts. I've spoken to Jack Goodman many times. I've done my own analysis. Yes I believe the video is real. In fact I have NO doubt about it. In fact I'm willing to bet you it's real. You name the amount. Let's both put our money where our mouths are. Whadayasay?



schroder said:
Do you have any evidence for this? The best I have seen is Swerdna’s turntable during the heterodyne run with a ratio of 2.4 : 1

You should really keep in mind that Swerdna has never done a "heterodyne" run. You know why that is? Because that's simply a bunch of nonsense that you made up.

I have seen exactly Zero evidence of anything greater than wind velocity.

Of course you haven't. How could you? Any evidence of faster than wind velocity is discounted by you by definition. It must either be a hoax, or doesn't fit within your extraordinarily limited understanding of physics.

schroder said:
Let us please leave sailboats and iceboats that are tacking at an angle, out of this discussion.

We're going to be talking about a lot of things we don't expect you to understand. Just pretend you're waiting for a friend at a rocket science convention. Don't let the big words bother you 'mmKay?

schroder said:
this thread can stop as soon as you admit to the following:

1) There is NO evidence at all that any cart has ever or will ever go directly down wind faster than the wind.

2) That what is happeneing on the turntable, while interesting, has NO relationship to what happens in the wind.

Let's add:

3) There is NO evidence that man has ever stepped foot on the moon

4) Global warming is a hoax being perpetrated by the government to control us.

5) Dr.'s don't want us to be healthy - just alive, so they can continue to bill us.

6) Of course they have cures for cancer and AIDS. But they'd never release them because treatment is such big business.

7) If "they" wanted to they could give us 200 mpg carbeurators, but big oil has paid off anyone that uncovers this truth - and then kills them.

8) The "chem trails" we see behind commercial jets are used by the government for mind control - and it's working.

9) The 9/11 attacks never really happened. And if they did, the U.S. government was behind the whole thing.

10) What holocaust?
 
  • #1,015
schroder said:
1) There is NO evidence at all that any cart has ever or will ever go directly down wind faster than the wind.

2) That what is happeneing on the turntable, while interesting, has NO relationship to what happens in the wind.


You know schroder - I refuse to believe you're as confused as you make yourself out to be. I think you're intentionally messing with people on this thread just to perpetuate this silliness. If I'm wrong - prove it to me. Prove you really believe what you say by taking my bet. Otherwise I'll have to conclude you're simply trolling.
 
<h2>1. What is the DDWFTTW Turntable Test?</h2><p>The DDWFTTW Turntable Test is a scientific experiment that aims to test the validity of the controversial "Double-Dark Warp Field Theory" proposed by physicist Harold White. It involves spinning a turntable at high speeds while measuring the weight of an object placed on it, in an attempt to detect any changes in weight that could indicate a warp field.</p><h2>2. What is the purpose of the 5-minute video?</h2><p>The 5-minute video is a condensed version of the full DDWFTTW Turntable Test, which can last up to 3 hours. It is meant to provide a quick overview of the experiment and its results, making it more accessible to a wider audience.</p><h2>3. Is the 5-minute video conclusive?</h2><p>The 5-minute video is not meant to be a conclusive proof of the Double-Dark Warp Field Theory. It is simply a demonstration of the experiment and its findings, which can then be further analyzed and studied by the scientific community.</p><h2>4. What were the results of the DDWFTTW Turntable Test?</h2><p>The results of the DDWFTTW Turntable Test showed a small but consistent decrease in the weight of the object placed on the spinning turntable. While this could potentially be attributed to a warp field, further research and testing is needed to confirm this hypothesis.</p><h2>5. What are the implications of the DDWFTTW Turntable Test?</h2><p>If the results of the DDWFTTW Turntable Test are confirmed by further experiments, it could have significant implications for our understanding of space-time and the possibility of faster-than-light travel. It could also potentially lead to new technologies and advancements in space exploration.</p>

1. What is the DDWFTTW Turntable Test?

The DDWFTTW Turntable Test is a scientific experiment that aims to test the validity of the controversial "Double-Dark Warp Field Theory" proposed by physicist Harold White. It involves spinning a turntable at high speeds while measuring the weight of an object placed on it, in an attempt to detect any changes in weight that could indicate a warp field.

2. What is the purpose of the 5-minute video?

The 5-minute video is a condensed version of the full DDWFTTW Turntable Test, which can last up to 3 hours. It is meant to provide a quick overview of the experiment and its results, making it more accessible to a wider audience.

3. Is the 5-minute video conclusive?

The 5-minute video is not meant to be a conclusive proof of the Double-Dark Warp Field Theory. It is simply a demonstration of the experiment and its findings, which can then be further analyzed and studied by the scientific community.

4. What were the results of the DDWFTTW Turntable Test?

The results of the DDWFTTW Turntable Test showed a small but consistent decrease in the weight of the object placed on the spinning turntable. While this could potentially be attributed to a warp field, further research and testing is needed to confirm this hypothesis.

5. What are the implications of the DDWFTTW Turntable Test?

If the results of the DDWFTTW Turntable Test are confirmed by further experiments, it could have significant implications for our understanding of space-time and the possibility of faster-than-light travel. It could also potentially lead to new technologies and advancements in space exploration.

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