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Homework Statement
A .3 kg ball is compressed a maximum of 0.6 cm when it strikes the floor at 9.29 m/s. Assuming acceleration is constant, what is the force the ball exerts on the floor?
Homework Equations
vf^2 = v0^2 + 2A(x-x0)
Once I find A it will be easy, since
F=MA
The Attempt at a Solution
0^2 = 9.29^2 + 2A (.006)
0 = 86.3041 + .012 A
-86.3041= .012A
-7192= A
F=MA
F=.3 (-7192)
F= -2157