Does the moon have greater gravitational force than the Sun on the Earth?

In summary, according to most sources, the moon has a greater effect on tides than the sun because the Earth moves around more in response to the moon's gravitational pull. However, tidal forces depend on the change in gravitational strength at different points, so the sun's force is greater on the oceans.
  • #1
tunakdude
3
0
I'm going nuts trying to figure this out... in textbooks and online, everything i read says that the moon and Earth have a much stronger gravitational force between them than the sun and the earth, and this is why the moon has greater effect on tides than the sun. They all say that this is because the moon, though much less massive than, is much closer to the Earth than the sun.

But... every time i do the calculations using the G(m1)(m2)/r^2, i get that the force between the Sun and the oceans is 8.37 x 10^18 N, and the force between the Moon and the oceans is 4.65 x 10^16 N

so my calculations say that the Sun has a greater force on the oceans than the moon... if i changed out the value of the oceans' mass with the Earth's mass, i still get that the sun has a greater gravitational pull on the Earth than the moon...

so why do all my sources say that the earth-moon gravitational force is greater?
thanks
 
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  • #2
You are confusing the gravitational force with tidal forces. The gravitational force varies with the inverse square of the distance between two bodies. Tidal forces result from the gradient of the gravitational force and thusly vary with the inverse cube of the distance. So while the gravitational force exerted by the sun on the Earth is much greater than that exerted by the moon, the situation is reverse for tidal forces.
 
  • #3
tunakdude said:
But... every time i do the calculations using the G(m1)(m2)/r^2, i get that the force between the Sun and the oceans is 8.37 x 10^18 N, and the force between the Moon and the oceans is 4.65 x 10^16 N
That equation gives you the gravitational force between the bodies, but that's not the tidal force. The tidal force depends on the change in gravitational strength at different points: It's the variation in pull on one side of the Earth compared to the pull on the other that creates the tidal force. The tidal force is inversely proportional to the distance cubed.

Read this: http://hyperphysics.phy-astr.gsu.edu/hbase/tide.html#mstid"
 
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  • #4
D H said:
You are confusing the gravitational force with tidal forces. The gravitational force varies with the inverse square of the distance between two bodies. Tidal forces result from the gradient of the gravitational force and thusly vary with the inverse cube of the distance. So while the gravitational force exerted by the sun on the Earth is much greater than that exerted by the moon, the situation is reverse for tidal forces.

thank you very much for the response...

but now i must ask, what is the "gradient of gravitational force" ??

why do you cube instead of square?
 
  • #5
Doc Al said:
That equation gives you the gravitational force between the bodies, but that's not the tidal force. The tidal force depends on the change in gravitational strength at different points: It's the variation in pull on one side of the Earth compared to the pull on the other that creates the tidal force. The tidal force is inversely proportional to the distance cubed.

Read this: http://hyperphysics.phy-astr.gsu.edu/hbase/tide.html#mstid"

ah, this makes good sense to me...
so tell me, do we see the moon having a greater periodic effect on tides than the sun because as the points on the Earth vary frequently with the moon, they experience a greater relative distance change with the moon than with the sun?

i thought that while searching around, i had read sources saying that gravitational force was greater, but they must have all said "tide-generating" potential or something like that (as does the Earth science textbook sitting in front of me)
 
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  • #7
tunakdude said:
why do you cube instead of square?

Because gravity in our universe is a three dimensional concept (4 but let's ignore time). Squaring would be x*x but gravity is divided into three dimensions, not two.
 
  • #8
Not really, no. What you are saying implies that Newton's gravitational force equation itself should be a cube function, but it isn't. And the tidal force equation comes simply from the derivative of that equation, since it is just the difference between two different gravitational forces: F1-F2=dF
 
  • #9
First of all, hello, this is my first post in this forum.
Second, excuse me everybody for opening such an old thread, but I have a question regarding Tidal forces.
How exactly did the OP come to 8.37 x 10^18 and 4.65 x 10^16 N respectively?
When I calculate the gravitational force of the Sun and of the Moon on the Earth I always get -3.5436^22 and -1.9830*10^20 rounded.
I`m using
b65000f8f887a68545ce63eb1cada232.png
 
  • #10
They are probably using the mass of the oceans rather than the mass of the Earth.
If you are just comparing forces it doesn't matter - it would be easier to compare the force on 1kg at the Earth

edit: if you use 1.37E21kg as the mass of the oceans it comes out about those numbers
 
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  • #11
Oh, I see. The second part of this particular problem wants me to show that the difference in gravitational force on both sides of the Earth is dF = (-2dr/r)*F.
I started at first using this http://en.wikipedia.org/wiki/Tidal_force#Mathematical_treatment , but it`s actually about acceleration and doesn`t get the job done. Any ideas would be greatly appreciated. :)

I mean simply calculating the derivative of the force gives the required result, but that seems too simple to me. Can it be?
 
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1. Does the moon always have a greater gravitational force than the Sun on the Earth?

Yes, the moon always has a greater gravitational force on the Earth than the Sun. This is because the moon is much closer to the Earth than the Sun, so its gravitational pull is stronger.

2. How does the distance between the Earth and the moon affect their gravitational forces?

The distance between the Earth and the moon directly affects their gravitational forces. The closer two objects are, the stronger their gravitational pull on each other. This is why the moon's gravitational force is greater than the Sun's on the Earth, as the moon is much closer to the Earth than the Sun.

3. Can the Sun's gravitational force on the Earth ever be greater than the moon's?

No, the Sun's gravitational force on the Earth can never be greater than the moon's. Even though the Sun is much larger and has a greater mass than the moon, its distance from the Earth is much greater. This means that its gravitational force is weaker compared to the moon's force on the Earth.

4. Does the moon's gravitational force affect the Earth's tides?

Yes, the moon's gravitational force plays a significant role in creating the Earth's tides. The moon's gravitational pull is strongest on the side of the Earth facing the moon, causing the water on that side to bulge towards the moon. This creates high tide. On the opposite side of the Earth, the water is pulled away from the moon, creating low tide.

5. How does the Earth's mass affect the gravitational forces of the moon and Sun?

The Earth's mass does not have a significant impact on the gravitational forces of the moon and Sun. The mass of an object does not affect its gravitational pull on other objects. However, the Earth's mass does affect its own gravitational pull on the moon and Sun, which is why they both orbit around the Earth.

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