Special Relativity - Twins sending light pulses

In summary, special relativity is a theory that explains the relationship between space and time and states that the laws of physics are the same for all observers in uniform motion. Light pulses play a crucial role in special relativity as they are used to measure the passage of time. Time dilation is a consequence of special relativity, where time passes slower for objects in motion compared to those at rest. The speed of light is constant for all observers, regardless of their relative speeds, and this affects the perception of time for observers in motion. Special relativity can also explain phenomena such as length contraction, mass-energy equivalence, and the relativity of simultaneity.
  • #1
jinksys
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Homework Statement


Twin A is on earth. Twin B is aboard a spacecraft that leaves Earth toward a start 12LY away at 0.6c.
Both twins send light pulses every year according to their clocks.
How many pulses does A send and receive and how many does send and receive if B makes a round trip to the star and back?

Homework Equations


The Attempt at a Solution



For twin A I need to know how long it takes B to complete the round trip.

time = d/r = 24LY/0.6c = 40 years

Twin a would send 39 pulses since B would arrive at year 40.

For twin B, the universe is moving past him at 0.6c so I need to compute the length of the trip according to his point of reference.

L = [tex]L_{0}[/tex][tex]\sqrt{1 - 0.6^2}[/tex] = 9.6LY

t = d/r = 18.6LY/0.6c = 32 years

Twin b would send 31 pulses since b would arrive at year 32.
 
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  • #2


However, according to the concept of time dilation in special relativity, time moves slower for objects in motion. This means that twin B would experience time at a slower rate compared to twin A, and therefore would not send or receive the same number of pulses as twin A.

To calculate the exact number of pulses sent and received by twin B, we can use the time dilation equation:

t' = t/\sqrt{1 - v^2/c^2}

Where t' is the time experienced by the moving object (twin B), t is the time experienced by the stationary object (twin A), v is the velocity of the moving object (0.6c in this case), and c is the speed of light.

For twin B's round trip, we can calculate the time experienced by twin B as:

t' = 40 years/\sqrt{1 - (0.6c)^2/c^2} = 66.7 years

This means that according to twin B's clock, the round trip would take 66.7 years. Therefore, twin B would send and receive 65 pulses (66.7 - 1 for the initial pulse) during the round trip.

In summary, the total number of pulses sent and received by twin A would be 39, while the total number of pulses sent and received by twin B would be 65. This is due to the difference in the experience of time between the two twins, as predicted by the theory of special relativity.
 

1. How does special relativity apply to twins sending light pulses?

Special relativity is a theory that explains the relationship between space and time. It states that the laws of physics are the same for all observers in uniform motion. This means that the perception of time and space can vary for different observers, depending on their relative speeds. In the case of twins sending light pulses, the twin who is traveling at a high speed will experience time passing slower than the twin who is stationary. This is known as time dilation.

2. What is the significance of light pulses in special relativity?

Light pulses play a crucial role in special relativity because they are used to measure the passage of time. According to the theory, the speed of light is constant for all observers, regardless of their relative speeds. This means that the time it takes for a light pulse to travel between two points will be the same for all observers. This allows us to make accurate measurements of time and distance, which are essential for understanding the effects of relativity.

3. Can you explain the concept of time dilation in the context of twins sending light pulses?

Time dilation is a consequence of special relativity, which states that time passes slower for objects in motion compared to those at rest. In the case of twins sending light pulses, one twin is moving at a high speed, while the other is stationary. The twin in motion will experience time passing slower due to their relative speed, while the stationary twin will experience time at a normal rate. This means that when the twins are reunited, the twin who traveled at a high speed will have aged less than the stationary twin.

4. How does the speed of light affect the perception of time for observers in motion?

The speed of light is constant for all observers, regardless of their relative speeds. This means that the perception of time will be different for observers in motion compared to those at rest. According to special relativity, as an observer's speed increases, time will appear to slow down for them. This is because the speed of light is the maximum speed at which information can travel, and as an observer's speed approaches the speed of light, time dilation becomes more significant.

5. What other phenomena can be explained by special relativity?

Special relativity can explain various phenomena, including length contraction, mass-energy equivalence, and the relativity of simultaneity. Length contraction refers to the shortening of an object's length in the direction of motion, as observed by an observer in a different frame of reference. Mass-energy equivalence, famously expressed by Einstein's equation E=mc^2, states that mass and energy are two forms of the same thing. The relativity of simultaneity states that events that are simultaneous for one observer may not be simultaneous for another, depending on their relative speeds.

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