Partial Pressure: Understanding CHCl3 & (C2H5)2O

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In summary, to calculate the chemical activity of chloroform and diethyl ether in a solution, you can use the formula aB = pB/p0B, where pB is the partial pressure of the component and p0B is the vapor pressure of the pure liquid. Temperature does not affect this calculation as long as it remains constant for all measurements. Molar fractions do not need to be considered unless the solution is not ideal, in which case the activity can be calculated using the reverse of the given formula by dividing the component's partial pressure by the total pressure.
  • #1
Brimley
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Hello everyone, I'm trying to understand more about how partial pressure works and how to use chemical activity equation. My reference text uses the following example:

Note1: A solution is prepared by mixing 2 moles of CHCl3 (chloroform) and 3 moles of (C2H5)2O (diethyl ether).
Note2: The vapor pressures of the components at 17 degrees C are pCHCl3 = 34 mmHg and p(C2H5)2O = 196 mmHg.
Note3: The vapor pressures of the pure liquids at 17 degrees C are p0CHCl3 = 143 mmHg and p0(C2H5)2O = 397 mmHg.

Using this information, shouldn't I be able to find the chemical activity for chloroform and ether?

Here are my tools:

aB = pB/p0B

where

aB = Chemical Activity
pB = partial pressure of B ? (gas / liquid ?)
p0B = vapor pressure of pure liquid B

I do not understand if this formula is complete or how to incorporate combining the moles of each substance or how temperature makes a difference. The reference texts just states that "the chemical activity of each substance can be obtained from the following formula" which is the formula I listed above. I also do not understand the distinction between Notes 2 and 3 regarding what the difference is between the vapor pressures of the "components" and of the "pure liquids" ... what does it mean for each?

Can anyone assist? Any all help is greatly appreciated!
 
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  • #2
Pressure of the component is just the partial pressure.

Pressure of pure liquid is a pressure of the saturated vapor that you would observe over the sample of a... pure liquid (100% of one component).

This is simple plug 'n chug.
 
  • #3
Brimley said:
I do not understand if this formula is complete or how to incorporate combining the moles of each substance or how temperature makes a difference. The reference texts just states that "the chemical activity of each substance can be obtained from the following formula" which is the formula I listed above.

Hello Borek, in my first post I wrote the text above explaining my confusion. I don't know if the book gives more information than necessary in their example or not, but I don't see how the formula plugs and chugs for having different moles of each substance nor do I understand where temperature makes a difference.

Could you help explain if the formula takes that into account in some way ? (i.e. you can only use it if the measurements are taken at the same temperature?) Also, how does it address the different moles of the substances given that they are forming a solution?
 
  • #4
Composition and temperature doesn't matter here - you can safely ignore them. Just use given pressures. Yes, it means you will calculate activities for the temperature at which pressures were measured.

For an ideal solution activity of a component should be identical to its molar fraction. Then the vapor pressure over the mixture follows Raoult's law (so partial pressure of the component can be calculated from its pressure over a pure component and its molar fraction in the mixture). For real solutions it is not exactly true.

So, if you have an ideal solution of a known composition, you can calculate activity of each component (simple - it will just equal its molar fraction) and use Raoult's law to calculate each component partial pressure, sum them and get total pressure. For a real solution you can do teh same, but you can't calculate activities that easily. However, you can also do the reverse - knowing total pressure and partial pressure of a given component you can divide the latter by the former to get the component activity. That's what you have to do here.
 
  • #5
Okay, so if I'm understanding you correctly, all I need to do is the following:

aCHCl3 = 34/143 = 0.2377
a(C2H5)2O = 196/397 = 0.4937

Is this correct? Are there any units?

So was I correct to say that since the temperature at which these measurements were made was constant, that temperature is not needed in the calculation? Does that infer that if the measurements at different temperatures were made that I couldn't have performed this calculation?

Also, I didn't have to do any molar fractions then, correct?
 
  • #6
Brimley said:
Is this correct?

Looks OK.

Are there any units?

No, activity is unitless.

So was I correct to say that since the temperature at which these measurements were made was constant, that temperature is not needed in the calculation? Does that infer that if the measurements at different temperatures were made that I couldn't have performed this calculation?

Yes & yes.

Also, I didn't have to do any molar fractions then, correct?

Yes.
 

1. What is partial pressure?

Partial pressure is the pressure exerted by a single gas component in a mixture of gases. It represents the hypothetical pressure that the gas would exert if it occupied the same volume alone at the same temperature.

2. How is partial pressure calculated?

Partial pressure is calculated by multiplying the total pressure of the gas mixture by the mole fraction of the gas component. The mole fraction is the ratio of moles of the gas component to the total moles of all gases in the mixture.

3. What is the significance of CHCl3 and (C2H5)2O in partial pressure?

CHCl3 and (C2H5)2O are two common solvents used in laboratory experiments. The partial pressure of these solvents is important in determining their vapor pressure, which affects their evaporation rate and potential health hazards.

4. Why is understanding partial pressure important in chemistry?

Partial pressure is important in chemistry because it helps determine the direction and extent of chemical reactions, as well as the solubility of gases in liquids. It also plays a role in gas laws, such as Boyle's Law and Dalton's Law of Partial Pressures.

5. How does temperature affect partial pressure?

According to the ideal gas law, the partial pressure of a gas is directly proportional to its temperature. This means that an increase in temperature will result in an increase in the partial pressure of the gas component in a mixture. However, this relationship is only true for ideal gases and may not hold for real gases at high pressures and low temperatures.

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