- #1
tleave2000
- 8
- 0
Hiya.
I got to an interesting bit in a calculus book, but as usual I'm stumped by a (probably simple) algebraic step.
The author goes from:
[tex](ds)^2=(dx)^2+(dy)^2[/tex]
to:
[tex]ds=\sqrt{1+\left(\frac{dy}{dx}\right)^2}dx[/tex]
I understand moving the square root across, but I don't understand how the right hand side in the first equation turns into what is under the square root in the second equation.
I hope someone can help. Cheers.
I got to an interesting bit in a calculus book, but as usual I'm stumped by a (probably simple) algebraic step.
The author goes from:
[tex](ds)^2=(dx)^2+(dy)^2[/tex]
to:
[tex]ds=\sqrt{1+\left(\frac{dy}{dx}\right)^2}dx[/tex]
I understand moving the square root across, but I don't understand how the right hand side in the first equation turns into what is under the square root in the second equation.
I hope someone can help. Cheers.
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