Why in a small unit of area for a surface S in an electric field

In summary, the use of the dot product of E and s in an electric field is necessary because it represents the amount of "air" passing through a small surface, similar to the concept of flux. This is because the dot product reflects the relationship between the electric field and the normal vector of the surface, with maximum flux occurring when these two vectors are parallel and minimum flux when they are perpendicular. This is a crucial concept in fluid dynamics, as the net flux determines the stability of a control volume.
  • #1
misogynisticfeminist
370
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I am wondering why in a small unit of area for a surface S in an electric field. The flux of the small area is the dot product of E and s where s is the normal vector and makes an angle theta to the field. Why do we use the dot product of E and s, why does it give us the flux of the small area?
 
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  • #2
Visualize the electric field as "wind". The dot product tells you how much
"air" is passing through the small surface. Don't take the analogy any further
than that- it's just a good way to visualize flux and dot products.
 
  • #3
You need to use the dot product because you need the amount "going in" to a surface. Imagine if you turn a can of coke on its side so that the circular ends are like vertical circles. Flux is the amount of whatever flowing through a given area. So like in the previous post, if the wind was perfectly vertical, nothing would enter the can from its ends. If we take the dot product of the winds direction with that of the outward normal from the ends caps we get 0. However, if the wind is perfectly horizontal we get some non zero value. (we actually need to take the negative of the dot product if we use the outward normal). That is if the outward normal of one end cap points to the left and the winds is to the right we would obtain a negative value for flux. This is incorrect as inward flux has a positive sign convention and outward flux has a negative sign convention. By taking the negative of left dot right we obtain some positive value which in this case is the magnitude of the air flow rate through the circular area of the left side of the can. In fluid dynamics flux is very important as the net flux determines whether or not a control volume maintains a steady state or not.
 
  • #4
misogynisticfeminist said:
I am wondering why in a small unit of area for a surface S in an electric field. The flux of the small area is the dot product of E and s where s is the normal vector and makes an angle theta to the field. Why do we use the dot product of E and s, why does it give us the flux of the small area?
Simple answer : "Because that's how the flux is defined" !
 
  • #5
To emphasise Gokul's point;

Flux is maximum when E is parallel to the surface normal, and zero when these two vectors are perpendicular. It is therefore intuitive to use a dot product to define the flux.

Claude.
 

1. Why is the electric field stronger in a smaller unit of area for a surface S?

The electric field is a measure of the force exerted on a unit of charge in an electric field. In a smaller unit of area, there are more charges concentrated, leading to a stronger force on a unit of charge, thus a stronger electric field.

2. How does the size of the surface S affect the electric field?

The size of the surface S directly affects the electric field. A smaller surface area will have a stronger electric field, while a larger surface area will have a weaker electric field, as the charges are more spread out.

3. What is the relationship between the electric field and the charge on the surface S?

The electric field is directly proportional to the charge on the surface S. This means that as the charge on the surface increases, the electric field also increases, and vice versa.

4. Why is the electric field perpendicular to the surface S?

The electric field is always perpendicular to the surface S because it is a measure of the force experienced by a charge placed on the surface. This force is always perpendicular to the surface at any given point.

5. How does the distance between the surface S and the source of the electric field affect the strength of the electric field?

The strength of the electric field is inversely proportional to the distance between the surface S and the source of the electric field. This means that as the distance increases, the electric field weakens, and as the distance decreases, the electric field strengthens.

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