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Femme_physics
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Just trying to check myself, as 14 bits doesn't seem to make sense...so I want to see how does it make sense. Is what written at the title true?
I suspect it's device specific.Is what written at the title true?
Femme_physics said:Just trying to check myself, as 14 bits doesn't seem to make sense...so I want to see how does it make sense. Is what written at the title true?
In this context, "14 bits at the output" refers to the number of bits (binary digits) that are being outputted by a system or device. "16 bits -2" refers to a specific binary number, in which the most significant bit (MSB) is set to 1 and the remaining 15 bits are zeros.
The MSB side is mentioned because it is important in understanding how the 14 bits at the output are related to the 16 bits -2. The MSB side refers to the most significant bit in a binary number, which carries the highest value and can greatly impact the overall value of the number.
14 bits is equivalent to 16 bits -2 on the MSB side because both represent the same binary number. In binary, each bit has a value of either 0 or 1, and the value of a number is determined by adding the values of each bit. So, 16 bits -2 has a value of 2^15 (32768) because the MSB is set to 1 and the remaining 15 bits are set to 0. Similarly, 14 bits also has a value of 2^14 (16384) because it has 14 bits set to 1 and the remaining 2 bits set to 0. Therefore, both numbers have the same value but are represented with a different number of bits.
The significance of having 14 bits at the output instead of 16 bits depends on the specific context and application. It could mean that the system or device is limited to only outputting 14 bits, which could impact the accuracy or precision of the output. It could also mean that the system has a lower resolution and can only output numbers up to 14 bits in length.
No, the number cannot be converted back to 16 bits with the same value. This is because the original number, 16 bits -2, was created by setting the most significant bit to 1 and the remaining 15 bits to 0. If we were to add 2 more bits to this number, the value would change and it would no longer be equivalent to the original number. However, if the 14 bits at the output were to be expanded to 16 bits by adding 2 more bits, the value could still be similar but not exactly the same.