Energy stored in a RLC circuit

[danbone87]

Homework Statement

A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply, then disconnected from the power and connected in series with a 0.220-{\rm mH} inductor.

Calculate the energy stored in the capacitor at time t = 0{\rm{ ms}} (the moment of connection with the inductor).

Calculate the energy stored in the inductor at t = 1.30 ms.

Homework Equations

i=-omegaQsin(omega*t)

and U=.5LI^2

I need to either find charge q or a resistance value to find I with and I'm stuck..

 

[alphysicist]

Hi danbone87,

A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply,

The way the capacitor is initially connected by itself to the battery will give you its initaial Q value.

I need to either find charge q or a resistance value to find I with and I'm stuck..

If I'm reading the problem correctly, there is no resistor; just a capacitor connected to an inductor.

 

[shabaz syed]

A 21.0 \mu F capacitor is charged by a 160.0-{\rm V} power supply, then disconnected from the power and connected in series with a 0.220-{\rm mH} inductor.

Calculate the energy stored in the capacitor at time t = 0{\rm{ ms}} (the moment of connection with the inductor).

Calculate the energy stored in the inductor at t = 1.30 ms.ans= q=cv=22u*160m gives u charge
energy=.5*22u*160m*160m=1/2(c*v*v)
now
VL=Ldi/dt