- #1
Kris1120
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Homework Statement
A current of 6.1 A is maintained in a single circular loop having a circumference of
110 cm. An external magnetic field of 5.5 T is
directed such that the angle between the field
and the plane of the loop is 42◦.
Determine the magnitude of the torque exerted on the loop by the magnetic forces acting upon it.
Answer in units of N · m.
Homework Equations
torque = N*I*A*B*sin(theta)
A=pi*r^2
C=2*pi*r
The Attempt at a Solution
r=1.1/(2*pi)
= 0.17507 m
A=pi*r^2
=pi*(0.17507 m)^2
=0.096288 m^2
torque = 1 loop * 6.1 A * 0.096288 m^2 * 5.5 T * sin(42)
= 2.1616 N*m