- #1
Taiki_Kazuma
- 24
- 0
What's the process that needs to take place to be able to graph the following equation (not-using a graphing calculator):
x2 + 12xy + 36y2 + 2x - 3y - 9 = 0
I know to use the B2 - 4AC formula to identify the equation as being parabolic, though I don't understand the formula...
Looking at the equation at first, I thought you could factor it to resemble something like:
(x2 = y or y2 = x)
But, that's where my thinking ended (or maybe it never actually began...)
Thanks!
x2 + 12xy + 36y2 + 2x - 3y - 9 = 0
I know to use the B2 - 4AC formula to identify the equation as being parabolic, though I don't understand the formula...
Looking at the equation at first, I thought you could factor it to resemble something like:
(x2 = y or y2 = x)
But, that's where my thinking ended (or maybe it never actually began...)
Thanks!